Operator in C: not greater and equal to.

Question

Just a fast question:

I'm trying to test if a variable is not greater than or equal to another variable.

I have it coded as such:

if (f!>=i){
print ("True");}

but my c compiler won't recognize it. I can't find it online, is it possible?

Solution 1

Just change it to (f < i) which is !(f >= i).

Note: this is not the case if either f or i is NaN. This is because f >= i will evaluate to false if either is NaN leading to !(f >= i) evaluating to true where f < i evaluates to false.

Solution 2

You want to do: if (!(f>=0))...

Specific to what you're doing, using < makes more sense. My suggestion here is just for a generic means of reversing polarity on any if statement.

Solution 3

Not greater than or equal to is equivalent to less than.

Solution 4

Use the aliter i.e instead of !> think in reverse and use f<i and you cant use ! for more than one operator i.e !+= is not valid

View more solutions

Comments

[chris]

! is a unary operator. It has to be applied to one thing, so think of what that one thing should be.

[Unknown]

You're going to have to expand on that.

[Lee Taylor]

Um, isn't that the same as if(f<i) ?

[Fantastic Mr Fox]

@LeeTaylor Yep, that is the answer that everyone below has provided.

[David Schwartz]

You're in luck! C has a "not greater than or equal to" operator. It's called "less than".

[Daniel Fischer]

It's unlikely to be important for your use case, but the pedant in me is compelled to note that f < i is not equivalent to !(f >= i) if a NaN is involved. A comparison with a NaN always returns 0 (false).

[mah]

@PeterO. What does this question have to do with the comma operator? Perhaps you mis-linked the possible duplicate?

[Peter O.]

@mah: Guess you're right. Unfortunately, I can't take back my vote to close.

[wizzwizz4]

This is not correct, as it will be true for anyvariablename == 0 which is unwanted.

[Sophie]

Please note that a < b is not the same as !(a >= b) for floating point types if either value was NaN.