PHP - How to update data to MySQL when click a radio button
Solution 1
Something to set you off on a prettier path:
// $_POST is way cooler than $_REQUEST
if (isset($_POST['gender']) && !empty($_POST['gender'])) {
// sql injection sucks
$gender = my_real_escape_string($_POST['gender']);
// cast it as an integer, sql inject impossible
$id = intval($_GET['id']);
if($id) {
// spit out the boolean INSERT result for use by client side JS
if(mysql_query("UPDATE users SET gender=$gender WHERE id=$id")) {
echo '1';
exit;
} else {
echo '0';
exit;
}
}
}
Assuming the same markup, an ajaxy solution (using jQuery):
<script>
var id = <?=$id?>;
// when the DOM is ready
$(document).ready(function() {
// 'click' because IE likes to choke on 'change'
$('input[name=gender]').click(function(e) {
// prevent normal, boring, tedious form submission
e.preventDefault();
// send it to the server out-of-band with XHR
$.post('save.php?id=' + id, function() {
data: $(this).val(),
success: function(resp) {
if(resp == '1') {
alert('Saved successfully');
} else {
alert('Oops, something went wrong!');
}
}
});
});
});
</script>
Solution 2
You can't do this with PHP alone ... you'll need some JavaScript on that page which executes onchanged
of the radiobutton(s) and executes a PHP script. This is called Asynchronous JavaScript and XML or "AJAX", and a quick introduction would be http://www.w3schools.com/ajax/default.asp
Solution 3
+1 to karim79 for pointing out jQuery/AJAX and $_POST thingy. Very important.
Here is a solution without jQuery(if you are not interested in learning jQuery right now)
Step 1: Add an onchange even on your checkbox tags like this:
<p><label><input name="gender" type="radio" value="male" onchange="do_submit()" <?php if($_POST['gender']=='male'){?>checked="checked"<? }?> /> Male</label></p>
<p><label><input name="gender" type="radio" value="female" onchange="do_submit()" <?php if($_POST['gender']=='female'){?>checked="checked"<? }?> /> Female</label></p>
Step 3: Add a name attribute to form tag like this:
<form name="myform" action="check.php" method="post">
Step 3: Write the onchange event handler function in javascript:
<script type="text/javascript">
function do_submit() {
document.forms['myform'].submit();
}
</script>
Couple of important things to note.
- $_POST is a better option than $_REQUEST.
- Use
<?php
instead of short form of php tag<?
. It will be deprecated in future versions of php. - Investing time in learning jQuery/AJAX is 100% worth the time and effort
Comments
-
wow almost 2 years
Example to save gender
<form action="save.php?id=<?=$id?>" method="post"> <p><label><input name="gender" type="radio" value="male" <?php if($gender=='male'){?>checked="checked"<? }?> /> Male</label></p> <p><label><input name="gender" type="radio" value="female" <?php if($gender=='female'){?>checked="checked"<? }?> /> Female</label></p> </form>
Here an example to update the value
if ($_REQUEST['gender']) { mysql_query("UPDATE users SET gender='$gender' WHERE id='" . $id . "'") or die(mysql_error()); }
How to make when we click on the gender the value will auto save to the db. Let me know.
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karim79 over 14 yearsUse the cody button with the 101010 in the input screen thingy.
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karim79 over 14 years@bob - that was just to provide additional insight, and hopefully spark some curiosity. Note, proper exception handling is missing and there's plenty of room for improvement (always!).
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Mir Nazim over 14 yearskarim79. I did and it correctly adjusts the code in the editor but does not works after submit :(
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karim79 over 14 yearsAh, the numbered points screwed it up. I have yet to figure that out ;)
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wow over 14 yearsyes always :) additional question. intval() better than (int)?
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karim79 over 14 years@bob - as far as I can tell, there's no difference, they both return a zero on failure. See php.net/manual/en/…