php preg_match to match chars at end of the string

Question

I have a below if statement, it never return True. What is wrong?

I am new to php and regex.

$String = '123456'; 
$Pattern = "/\d{2}$/"; 

//i intend to match '56', which is the last two digit of the string.

if(preg_match($Pattern $String ,$matches))
{
 echo 'Matched';
}

if the $Pattern is "/^\d{2}/", true is returned and matched the number '12';

Edit: My mistake. The above code work well. In actual code, the $String is assigned from a variable and it alwasys end up with a dot which i unawared of. The requirement to match the last two digits above is just for issue explanation. Regex is require in actual code.

Solution

You are correct.

$String = '123456';
$Pattern = "/\d{2}$/";
$Pattern2 = "/^\d{2}/";

if(preg_match($Pattern, $String ,$matches))
{
    print_r($matches); // 56
}

if(preg_match($Pattern2, $String ,$matches))
{
    print_r($matches); // 12
}