Printing Function Address

Question

I've been trying a way to figure out how to print the address of the function, This is what I came up with

#include<stdio.h>
int test(int a, int b)
{
     return a+b;
}
int main(void)
{
     int (*ptr)(int,int);
     ptr=&test;
     printf("The address of the function is =%p\n",ptr);
     printf("The address of the function pointer is =%p\n",&ptr);
     return 0;
}

It o/p something like this without any warning and errors

address of function is =0x4006fa
address of function pointer  is =0x7fffae4f73d8

My question whether using %p format specifier is the correct way to print the address of the function or is there any other way to do so?

Solution 1

This is not correct. %p is only for object pointer types (in fact, void * specifically). There is no format specifier for a function pointer.

Solution 2

Without using the separate pointer for print the address of the function, You can use the name of the function in the printf.

 printf("The address of the function is =%p\n",test);

For printing the address in the hexa-decimal format you can use the %p.