Python datetime - setting fixed hour and minute after using strptime to get day,month,year

Question

I've successfully converted something of 26 Sep 2012 format to 26-09-2012 using:

datetime.strptime(request.POST['sample_date'],'%d %b %Y')

However, I don't know how to set the hour and minute of something like the above to 11:59. Does anyone know how to do this?

Note, this can be a future date or any random one, not just the current date.

Solution 1

Use datetime.replace:

from datetime import datetime
dt = datetime.strptime('26 Sep 2012', '%d %b %Y')
newdatetime = dt.replace(hour=11, minute=59)

Also worth noting: datetime.replace returns a new copy of the datetime (since datetime is immutable): it is like str.replace in that regard.

Solution 2

datetime.replace() will provide the best options. Also, it provides facility for replacing day, year, and month.

Suppose we have a datetime object and date is represented as: "2017-05-04"

>>> from datetime import datetime
>>> date = datetime.strptime('2017-05-04',"%Y-%m-%d")
>>> print(date)
2017-05-04 00:00:00
>>> date = date.replace(minute=59, hour=23, second=59, year=2018, month=6, day=1)
>>> print(date)
2018-06-01 23:59:59

Solution 3

If you have a date as a datetime.datetime (or a datetime.date) instance and want to combine it via a time from a datetime.time instance, then you can use the classmethod datetime.datetime.combine:

import datetime
dt = datetime.datetime(2020, 7, 1)
t = datetime.time(12, 34)
combined = datetime.datetime.combine(dt.date(), t)

Solution 4

Shortcuts to convert datetime to max or min

import datetime

def dt_time_min(dt):
    """converts any datetime/date to new datetime with same date and time=0:00:00"""
    return datetime.datetime.combine(dt, datetime.time.min)


def dt_time_max(dt):
    """converts any datetime/date to new datetime with same date and time=23:59:59.999999"""
    return datetime.datetime.combine(dt, datetime.time.max)

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Comments

[nneonneo]

Yes, just do date = datetime.strptime('26 Sep 2012', '%d %b %Y').replace(hour=11, minute=59). I used the extra variable so that the line wasn't too long :)

[nneonneo]

Also worth noting: datetime.replace returns a new copy of the datetime (since datetime is immutable): it is like str.replace in that regard.

[PV8]

How can i remove everything after '2016-06-01' so that hour minute and second disappear?

[Samuel Dauzon]

What's your answer's added value against nneonneo's answer posted 5 years before yours ?

[Flimm]

@PV8 If you want a datetime, run: r = dt.replace(hour=0, minute=0, second=0, microsecond=0). If you want a date object, run: r = dt.date()