Python, writing an integer to a '.txt' file
69,335
Solution 1
I think it's simpler doing:
number = 1337
with open('filename.txt', 'w') as f:
f.write('%d' % number)
But it really depends on your use case.
Solution 2
Write
result = 1
f = open('output1.txt','w') # w : writing mode / r : reading mode / a : appending mode
f.write('{}'.format(result))
f.close()
Read
f = open('output1.txt', 'r')
input1 = f.readline()
f.close()
print(input1)
Solution 3
With python 2, you can also do:
number = 1337
with open('filename.txt', 'w') as f:
print >>f, number
I personally use this when I don't need formatting.
Author by
clickonMe
Updated on April 23, 2021Comments
-
clickonMe about 3 years
Would using the pickle function be the fastest and most robust way to write an integer to a text file?
Here is the syntax I have so far:
import pickle pickle.dump(obj, file)
If there is a more robust alternative, please feel free to tell me.
My use case is writing an user input:
n=int(input("Enter a number: "))
- Yes, A human will need to read it and maybe edit it
- There will be 10 numbers in the file
- Python may need to read it back later.