Remote desktop to a VM that is on ESXi v4.0

138

Solution 1

Have you enabled Remote Desktop on the VM itself?

Start+PauseBreak > Remote > Check 'Allow users to remotely connect'

Solution 2

In general I always check:

  • Will the firewall allow my connection?
  • Is remote desktop allowed?
  • Is remote desktop configured to allow requesting client's remote desktop version?
  • Do I have the network enabled and configured on every dependent device? (This is actually overlooked sometimes..)
  • Do the windows license allow more than one concurrent session? If not; is no one else using the host at the moment?

I hope this helps.

Solution 3

I had to enable the RDP in Terminal Services Configuration and pick the Vmware virtual interface. I did get a prompt once I went to the adpaters tab that the the interfacoe had changed and I needed to select one.

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Tim Woods
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Tim Woods

Updated on September 17, 2022

Comments

  • Tim Woods
    Tim Woods over 1 year

    Hello I am new to xml and would like to compare some values using an xsl stylesheet

    `<a>
     <b>   <name>foo</name>   </b>
     <b>   <name>bar</name>   </b>
     <b>   <name>fred</name>  </b>
     <b>   <name>fred</name>  </b>
     </a>`
    

    I would like to write a style sheet that checks all the b nodes and returns the values that have the same value so using the simple example above i would like the output to resemble :
    "Your duplicate strings are fred"

    I have used a for each loop to return all the values but comparing the names and returning the duplicates has eluded me.If possible i would like to achieve the comparison by the use of a while type loop.

    Thank you for any help.

  • Tomalak
    Tomalak almost 12 years
    +1 pragmatic solution. On a general note, you should avoid "naked" text nodes in your XSL. Rather use <xsl:text>.
  • Tim Woods
    Tim Woods almost 12 years
    Thank you very much for your insight and help this solution worked for me very well.
  • Tim Woods
    Tim Woods almost 12 years
    Thank you very much for your insight and help this solution worked for me very well.
  • Dimitre Novatchev
    Dimitre Novatchev almost 12 years
    @tomalak: This certainly can be done a little bit more efficiently, not using count() and without any xsl:for-each .
  • Tomalak
    Tomalak almost 12 years
    @Dimitre That's why I gave my +1 to your answer. :)
  • Dimitre Novatchev
    Dimitre Novatchev almost 12 years
    @Tomalak: The XSLT 2.0 solution and the XPath 2.0 one-liner could also be interesting to you :)