Remote desktop to a VM that is on ESXi v4.0
Solution 1
Have you enabled Remote Desktop on the VM itself?
Start+PauseBreak > Remote > Check 'Allow users to remotely connect'
Solution 2
In general I always check:
- Will the firewall allow my connection?
- Is remote desktop allowed?
- Is remote desktop configured to allow requesting client's remote desktop version?
- Do I have the network enabled and configured on every dependent device? (This is actually overlooked sometimes..)
- Do the windows license allow more than one concurrent session? If not; is no one else using the host at the moment?
I hope this helps.
Solution 3
I had to enable the RDP in Terminal Services Configuration and pick the Vmware virtual interface. I did get a prompt once I went to the adpaters tab that the the interfacoe had changed and I needed to select one.
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Tim Woods
Updated on September 17, 2022Comments
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Tim Woods over 1 year
Hello I am new to xml and would like to compare some values using an xsl stylesheet
`<a> <b> <name>foo</name> </b> <b> <name>bar</name> </b> <b> <name>fred</name> </b> <b> <name>fred</name> </b> </a>`
I would like to write a style sheet that checks all the b nodes and returns the values that have the same value so using the simple example above i would like the output to resemble :
"Your duplicate strings are fred"I have used a for each loop to return all the values but comparing the names and returning the duplicates has eluded me.If possible i would like to achieve the comparison by the use of a while type loop.
Thank you for any help.
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Tomalak almost 12 years+1 pragmatic solution. On a general note, you should avoid "naked" text nodes in your XSL. Rather use
<xsl:text>
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Tim Woods almost 12 yearsThank you very much for your insight and help this solution worked for me very well.
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Tim Woods almost 12 yearsThank you very much for your insight and help this solution worked for me very well.
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Dimitre Novatchev almost 12 years@tomalak: This certainly can be done a little bit more efficiently, not using
count()
and without anyxsl:for-each
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Tomalak almost 12 years@Dimitre That's why I gave my +1 to your answer. :)
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Dimitre Novatchev almost 12 years@Tomalak: The XSLT 2.0 solution and the XPath 2.0 one-liner could also be interesting to you :)