Remove the 0b in binary

Question

I am trying to convert a binary number I have to take out the 0b string out.

I understand how to get a bin number

x = 17

print(bin(17))

'0b10001'

but I want to take the 0b in the string out and I am having some issues with doing this. This is going to be within a function returning a binary number without the 0b.

Solution 1

Use slice operation to remove the first two characters.

In [1]: x = 17

In [2]: y = bin(x)[2:]

In [3]: y
Out[3]: '10001'

Solution 2

It's easy just make this function:

def f(n):print('{:0b}'.format(n))
f(17)
>>> 10001

Solution 3

use python string slice operation.

a = bin(17)
b = bin(17)[2:]

to format this to 8-bits use zfill.

c = b.zfill(8) 

Solution 4

format(17, 'b')
>>> '10001'

Use the format() builtin. It also works for hexadecimal, simply replace 'b' with 'x'.

https://docs.python.org/3/library/functions.html#format

Solution 5

with Python 3.6 you can use f-strings

print( f'{x:b}' )
'10001'

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Comments

[mbpaulus]

beware, for 0 this returns an empty string.

[NikT]

hexadecimal is 'x', not 'h' -- for all specifiers, see docs.python.org/3/library/…