replace() method not working on Pandas DataFrame

Question

I have looked up this issue and most questions are for more complex replacements. However in my case I have a very simple dataframe as a test dummy.

The aim is to replace a string anywhere in the dataframe with an nan, however this does not seem to work (i.e. does not replace; no errors whatsoever). I've tried replacing with another string and it does not work either. E.g.

d = {'color' : pd.Series(['white', 'blue', 'orange']),
   'second_color': pd.Series(['white', 'black', 'blue']),
   'value' : pd.Series([1., 2., 3.])}
df = pd.DataFrame(d)
df.replace('white', np.nan)

The output is still:

      color second_color  value
  0   white        white      1
  1    blue        black      2
  2  orange         blue      3

Solution 1

You need to assign back

df = df.replace('white', np.nan)

or pass param inplace=True:

In [50]:
d = {'color' : pd.Series(['white', 'blue', 'orange']),
   'second_color': pd.Series(['white', 'black', 'blue']),
   'value' : pd.Series([1., 2., 3.])}
df = pd.DataFrame(d)
df.replace('white', np.nan, inplace=True)
df

Out[50]:
    color second_color  value
0     NaN          NaN    1.0
1    blue        black    2.0
2  orange         blue    3.0

Most pandas ops return a copy and most have param inplace which is usually defaulted to False

Solution 2

Given that this is the top Google result when searching for "Pandas replace is not working" I'd like to also mention that:

replace does full replacement searches, unless you turn on the regex switch. Use regex=True, and it should perform partial replacements as well.

This took me 30 minutes to find out, so hopefully I've saved the next person 30 minutes.

Solution 3

Neither one with inplace=True nor the other with regex=True don't work in my case. So I found a solution with using Series.str.replace instead. It can be useful if you need to replace a substring.

In [4]: df['color'] = df.color.str.replace('e', 'E!')
In [5]: df  
Out[5]: 
     color second_color  value
0   whitE!        white    1.0
1    bluE!        black    2.0
2  orangE!         blue    3.0

or even with a slicing.

In [10]: df.loc[df.color=='blue', 'color'] = df.color.str.replace('e', 'E!')
In [11]: df  
Out[11]: 
    color second_color  value
0   white        white    1.0
1   bluE!        black    2.0
2  orange         blue    3.0

Solution 4

When you use df.replace() it creates a new temporary object, but doesn't modify yours. You can use one of the two following lines to modify df:

df = df.replace('white', np.nan)
df.replace('white', np.nan, inplace = True)

Solution 5

You might need to check the data type of the column before using replace function directly. It could be the case that you are using replace function on Object data type, in this case, you need to apply replace function after converting it into a string.

Wrong:

df["column-name"] = df["column-name"].replace('abc', 'def')

Correct:

df["column-name"] = df["column-name"].str.replace('abc', 'def')

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