SET a variable in SELECT statement - MySQL
Solution 1
The issue is that you cannot mix select
and set
in one statement, there'll surely be syntax error:
select*from t where 1 and set@a=1;
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'set@a=1' at line 1
If you want to do set
within select
, use the colon equals syntax. Change this:
select*from t where 1 and set@a=1;
into:
select*,@a:=1 from t where 1;
Here's how you update the variable upon each row:
create table t(id int); insert t values(1),(2),(3);
set@a=0;
select@a:=id from t;
+--------+ | @a:=id | +--------+ | 1 | | 2 | | 3 | +--------+
And you can even do concat
:
set@a='0';
select @a:=concat(@a,',',id)from t;
+-----------------------+ | @a:=concat(@a,',',id) | +-----------------------+ | 0,1 | | 0,1,2 | | 0,1,2,3 | +-----------------------+
Or concat
without the leading 0
:
set@a='';
select @a:=concat(@a,if(@a='','',','),id)from t;
+------------------------------------+ | @a:=concat(@a,if(@a='','',','),id) | +------------------------------------+ | 1 | | 1,2 | | 1,2,3 | +------------------------------------+
However, the manual explicitly states that this is dangerous:
...you should never assign a value to a user variable and read the value within the same statement...
...you might get the results you expect, but this is not guaranteed.
...the order of evaluation for expressions involving user variables is undefined.
This has also been mentioned on Xaprb.
Lastly, if you're doing quirky things like assigning differing value types to the variable and etc, checkout the manual to be sure you understand the intricate mechanisms.
Solution 2
Then you might write your query like this.
SET @rejects = '';
SELECT @rejects = CONCAT(@rejects,',',src) FROM list WHERE maker = 1 AND by_ids IN ('10','11') AND country LIKE '%I%' AND
(src IS NULL OR src NOT IN (@rejects) AND checkSrc(src) = 'yes');
SELECT @rejects;
Comments
-
Andrew Eisenberg almost 4 years
I'm using this code which has an error:
SET @rejects = ''; SELECT * FROM list WHERE maker = 1 AND by_ids IN ('10','11') AND country LIKE '%I%' AND ( src IS NULL || src NOT IN (@rejects) AND checkSrc(src) = 'yes' AND SET @rejects = CONCAT(@rejects,',',src) );
What's causing the issue?
-
fedorqui about 11 yearsCould be
by_ids INT('10','11')
toby_ids IN('10','11')
? -
Ravindra Gullapalli about 11 yearsWhy
AND SET @rejects = CONCAT(@rejects,',',src)
inWHERE
clause? -
Andrew Eisenberg about 11 yearsThats what i want, i want to concat the value of each searched src into @rejects variable.
-
mko about 11 years|| should not be used as an or.
-
Admin about 11 yearsYou can see examples when searching for "MySQL group by greatest/top n" or similar - this is because MySQL solutions require some interesting hacks (usually just incrementing a counter).
-
-
Ravindra Gullapalli about 11 yearsWhat is your expected output? Also if src is null then there could be a problem. Can you post your table structure and expected output?
-
Philipp about 3 years"...you should never assign a value to a user variable and read the value within the same statement..." that saved me a lot of trial-and-error.