Sparse matrix to a data frame in R
21,048
Solution 1
Using summary
, here is an example:
mat <- Matrix(data = c(1, 0, 2, 0, 0, 3, 4, 0, 0), nrow = 3, ncol = 3,
dimnames = list(Origin = c("A", "B", "C"),
Destination = c("X", "Y", "Z")),
sparse = TRUE)
mat
# 3 x 3 sparse Matrix of class "dgCMatrix"
# Destination
# X Y Z
# A 1 . 4
# B . . .
# C 2 3 .
summ <- summary(mat)
summ
# 3 x 3 sparse Matrix of class "dgCMatrix", with 4 entries
# i j x
# 1 1 1 1
# 2 3 1 2
# 3 3 2 3
# 4 1 3 4
data.frame(Origin = rownames(mat)[summ$i],
Destination = colnames(mat)[summ$j],
Weight = summ$x)
# Origin Destination Weight
# 1 A X 1
# 2 C X 2
# 3 C Y 3
# 4 A Z 4
Solution 2
df <- as.data.frame(as.matrix(mat))
as.matrix
will turn the sparse matrix to a dense matrix, if it is not too large:-) Then you can convert it to a data frame.
(mat
is the example dgCMatrix from @flodel 's answer)
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Author by
Seen
Updated on July 09, 2022Comments
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Seen almost 2 years
I have a sparse matrix
Formal class 'dgCMatrix' [package "Matrix"] with 6 slots ..@ i : int [1:37674] 1836 2297 108 472 1735 1899 2129 2131 5 67 ... ..@ p : int [1:3417] 0 2 8 22 25 35 44 45 45 47 ... ..@ Dim : int [1:2] 3416 3416 ..@ Dimnames:List of 2 .. ..$ : chr [1:3416] "AAA" "AAE" "AAL" "AAN" ... .. ..$ : chr [1:3416] "AAA" "AAE" "AAL" "AAN" ... ..@ x : num [1:37674] 1 1 1 1 1 1 1 1 1 1 ... ..@ factors : list()
What is a fast way to convert this matrix to a list as (except for a
for loop
):Origin Destination Weight AAA AAE 4 AAL AAN 5
Note: I only need to get the Origin and Destination for Weight>0
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Chase almost 12 years
library(reshape2); dcast(Origin ~ Destination, data = dat, subset = Weight != 0)
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cloudscomputes over 4 yearsThis doesn't give back what the sparse matrix's original pattern