SpringApplication.run main method
Solution 1
You need to run Application.run()
because this method starts whole Spring Framework. Code below integrates your main()
with Spring Boot.
Application.java
@SpringBootApplication
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
}
}
ReconTool.java
@Component
public class ReconTool implements CommandLineRunner {
@Override
public void run(String... args) throws Exception {
main(args);
}
public static void main(String[] args) {
// Recon Logic
}
}
Why not SpringApplication.run(ReconTool.class, args)
Because this way spring is not fully configured (no component scan etc.). Only bean defined in run() is created (ReconTool).
Example project: https://github.com/mariuszs/spring-run-magic
Solution 2
Using:
@ComponentScan
@EnableAutoConfiguration
public class Application {
public static void main(String[] args) {
SpringApplication.run(Application.class, args);
//do your ReconTool stuff
}
}
will work in all circumstances. Whether you want to launch the application from the IDE, or the build tool.
Using maven just use mvn spring-boot:run
while in gradle it would be gradle bootRun
An alternative to adding code under the run method, is to have a Spring Bean that implements CommandLineRunner
. That would look like:
@Component
public class ReconTool implements CommandLineRunner {
@Override
public void run(String... args) throws Exception {
//implement your business logic here
}
}
Check out this guide from Spring's official guide repository.
The full Spring Boot documentation can be found here
![Alexander Mills](https://i.stack.imgur.com/5Oh7r.jpg?s=256&g=1)
Alexander Mills
Dev, Devops, soccer coach. https://www.github.com/oresoftware
Updated on July 09, 2022Comments
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Alexander Mills almost 2 years
I created a project in Eclipse using the Spring Starter project template.
It automatically created an Application class file, and that path matches the path in the POM.xml file, so all is well. Here is the Application class:
@Configuration @ComponentScan @EnableAutoConfiguration public class Application { public static void main(String[] args) { //SpringApplication.run(ReconTool.class, args); ReconTool.main(args); } }
This is a command line app that I am building and in order to get it to run I had to comment out the SpringApplication.run line and just add the main method from my other class to run. Other than this quick jerry-rig, I can build it using Maven and it runs as a Spring application, sort of.
I'd rather, however, not have to comment out that line, and use the full Spring framework. How can I do this?
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MariuszS about 10 yearsYou steal all my ideas :)
-
geoand about 10 yearsIt seams like we are thinking in parallel :)
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Alexander Mills about 10 yearsI think you meant: SpringApplication.run(ReconTool.class, args);
-
MariuszS about 10 yearsNo,
RecontTool
has@Component
added, so spring will executeRecontTool.run()
andRecontTool.main()
ofcourse :) -
MariuszS about 10 yearsBut you are true,
SpringApplication.run(ReconTool.class, args)
works too :) -
MariuszS about 10 yearsI would rather leave
SpringApplication.run(Application.class
because this works, second solution looks too magic to me :) -
MariuszS about 10 yearsYour solution works without
@Component
:) github.com/mariuszs/spring-run-magic -
Villat about 5 yearsNowadays, you could replace
@Configuration
,@ComponentScan
and@EnableAutoConfiguration
and use@SpringBootApplication
instead