Sum List of BigDecimal
Solution 1
Here is a way to do it with only Java 8 and streams:
List<BigDecimal> list = Arrays.asList(new BigDecimal(10.333), //
new BigDecimal(14.333));
BigDecimal result = list.stream().reduce(BigDecimal.ZERO, BigDecimal::add);
Solution 2
If you can't use Java 8 lambdas or Groovy closures, in which case you could write a one-liner to replace your four lines, the code you have is thoroughly clear. Using a library-based iteration tool will almost certainly make the code more complicated and will certainly make it slower. You made it about as simple as it gets; it's fine.
Solution 3
If you don't mind the extra third-party library dependency, then there is a solution for this problem in Eclipse Collections.
List<BigDecimal> list =
Lists.mutable.with(
new BigDecimal("10.333"),
new BigDecimal("14.333"));
Assert.assertEquals(
new BigDecimal("24.666"),
Iterate.sumOfBigDecimal(list, Functions.getPassThru()));
Since you have a list of BigDecimal already, the function that is applied to each just passes the value through.
Note: I am a committer for Eclipse Collections
AJJ
Loves to Code. Loves to learn new technology and frameworks. Likes Web development the most.
Updated on August 16, 2022Comments
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AJJ over 1 year
I am working on a project with Spring and Maven and Java 7.
I have a list with bigdecimal and have to sum up all the elements in the list. i know using for loop we can to as below,
List<BigDecimal> list = new ArrayList<BigDecimal>(); list.add(new BigDecimal(10.333)); list.add(new BigDecimal(14.333)); BigDecimal result = new BigDecimal(0); for (BigDecimal b : list) { result = result.add(b); }
Is there a better way to do? using google gauva FluentIterable or apache ArrayUtils/StatUtils?
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Holger over 8 yearsExactly. Well, replacing the initial value
new BigDecimal(0)
withBigDecimal.ZERO
, but that’s it. Nothing more to improve…