SwiftyJSON object back to string

26,562

Solution 1

From the README of SwiftyJSON on GitHub:

//convert the JSON to a raw String
if let string = libraryObject.rawString() {
//Do something you want
  print(string)
}

Solution 2

//convert the JSON to a raw String
if let strJson = jsonObject.rawString() {
    // 'strJson' contains string version of 'jsonObject'
}

//convert the String back to JSON (used this way when used with Alamofire to prevent errors like Task .<1> HTTP load failed (error code: -1009 [1:50])
if let data = strJson.data(using: .utf8) {
    if let jsonObject = try? JSON(data: data) {
        // 'jsonObject' contains Json version of 'strJson'
    }
}
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26,562
Derek
Author by

Derek

Updated on October 07, 2020

Comments

  • Derek
    Derek over 3 years

    I'm using the SwiftyJSON library to parse JSON into swift objects. I can create the JSON object and read and write to it

    // Create json object to represent library
    var libraryObject = JSON(["name":"mylibrary","tasks":["Task1","Task2","Task3"]])
    
    
        // Get
        println(libraryObject["name"])
        println(libraryObject["tasks"][0])
    
        // Set
        println("Setting first task to 'New Task'")
        libraryObject["tasks"][0] = "New Task"
    
        // Get
        println(libraryObject["tasks"][0])
    
        // Convert object to JSON and print
        println(libraryObject)
    

    All of this works as expected. I just want to convert the libraryObject back to a string in JSON format!

    The println(libraryObject) command outputs what I want to the console but I can't find a way to get it as a string.

    libraryObject.Stringvalue and libraryObject.String both return empty values but when I try eg println("content: "+libraryObject) I get an error trying to append a String to a JSON

  • Derek
    Derek almost 9 years
    I swear I did but just had a total blindspot! Thanks a lot
  • Andy
    Andy almost 7 years
    be sure to use .rawString() and not .rawString (without brackets). Spent ages trying to work out why I wasn't getting the same result.