Using PATINDEX to find varying length patterns in T-SQL
Solution 1
I blogged about this a while ago. Extracting numbers with SQL server
Declare @Temp Table(Data VarChar(100))
Insert Into @Temp Values('some text 456.09 other text')
Insert Into @Temp Values('even more text 98273.453 la la la')
Insert Into @Temp Values('There are no numbers in this one')
Select Left(
SubString(Data, PatIndex('%[0-9.-]%', Data), 8000),
PatIndex('%[^0-9.-]%', SubString(Data, PatIndex('%[0-9.-]%', Data), 8000) + 'X')-1)
From @Temp
Solution 2
Wildcards.
SELECT PATINDEX('%[0-9]%[0-9].[0-9]%[0-9]%','some text 456.09 other text')
SELECT PATINDEX('%[0-9]%[0-9].[0-9]%[0-9]%','even more text 98273.453 la la la')
Solution 3
Yes you need to link to the clr to get regex support. But if PATINDEX does not do what you need then regex was designed exactly for that.
http://msdn.microsoft.com/en-us/magazine/cc163473.aspx
Solution 4
Should be checked for robustness (what if you only have an int, for example), but this is just to put you on a track:
if exists (select routine_name from information_schema.routines where routine_name = 'GetFirstFloat')
drop function GetFirstFloat
go
create function GetFirstFloat (@string varchar(max))
returns float
as
begin
declare @float varchar(max)
declare @pos int
select @pos = patindex('%[0-9]%', @string)
select @float = ''
while isnumeric(substring(@string, @pos, 1)) = 1
begin
select @float = @float + substring(@string, @pos, 1)
select @pos = @pos + 1
end
return cast(@float as float)
end
go
select dbo.GetFirstFloat('this is a string containing pi 3.14159216 and another non float 3 followed by a new fload 5.41 and that''s it')
select dbo.GetFirstFloat('this is a string with no float')
select dbo.GetFirstFloat('this is another string with an int 3')
Comments
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Rich almost 2 years
I'm looking to pull floats out of some varchars, using PATINDEX() to spot them. I know in each varchar string, I'm only interested in the first float that exists, but they might have different lengths.
e.g.
'some text 456.09 other text' 'even more text 98273.453 la la la'
I would normally match these with a regex
"[0-9]+[.][0-9]+"
However, I can't find an equivalent for the + operator, which PATINDEX accepts. So they would need to be matched (respectively) with:
'[0-9][0-9][0-9].[0-9][0-9]' and '[0-9][0-9][0-9][0-9][0-9].[0-9][0-9][0-9]'
Is there any way to match both of these example varchars with one single valid PATINDEX pattern?