WebView link click open default browser

123,123

Solution 1

I had to do the same thing today and I have found a very useful answer on StackOverflow that I want to share here in case someone else needs it.

Source (from sven)

webView.setWebViewClient(new WebViewClient(){
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
        if (url != null && (url.startsWith("http://") || url.startsWith("https://"))) {
            view.getContext().startActivity(
                new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
            return true;
        } else {
            return false;
        }
    }
});

Solution 2

WebView webview = (WebView) findViewById(R.id.webview);
webview.loadUrl(https://whatoplay.com/);

You don't have to include this code.

// webview.setWebViewClient(new WebViewClient());

Instead use below code.

webview.setWebViewClient(new WebViewClient()
{
  public boolean shouldOverrideUrlLoading(WebView view, String url)
  {
    String url2="https://whatoplay.com/";
     // all links  with in ur site will be open inside the webview 
     //links that start ur domain example(http://www.example.com/)
    if (url != null && url.startsWith(url2)){
      return false;
    } 
     // all links that points outside the site will be open in a normal android browser
    else
    {
      view.getContext().startActivity(
      new Intent(Intent.ACTION_VIEW, Uri.parse(url)));
      return true;
    }
  }
});

Solution 3

You only need to add the following line

yourWebViewName.setWebViewClient(new WebViewClient());

Check this for official documentation.

Solution 4

you can use Intent for this:

Intent browserIntent = new Intent("android.intent.action.VIEW", Uri.parse("your Url"));
startActivity(browserIntent);

Solution 5

You can use an Intent for this:

Uri uriUrl = Uri.parse("http://www.google.com/"); 
Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);  
startActivity(launchBrowser);

View more solutions

123,123

Author by

Kyle

Updated on February 18, 2021

Comments

Kyle about 3 years

Right now I have an app that loads a webview and all the clicks are kept within the app. What I would like to do is when a certain link, for example, http://www.google.com is clicked within the app it opens the default browser. If anyone has some ideas please let me know!
rajh2504 almost 13 years

you should use Intent.ACTION_VIEW
Android-Droid over 12 years

this answer helped me a lot! Thanks!
Johan S almost 11 years

Note that if the url is relative, (doesn't start with "http://") then it will open inside the app. To avoid this always return true and make relative url links do nothing.
Abhinav Saxena about 10 years

You should check for other protocols in the prefix like rtsp, https and so on. If the links are intended to open a media, it should be redirected to device's media player. If there is no protocol prefix, then identify and provide one.
Sudarshan about 8 years

Exact, what I am searching. Thanks
Atieh about 8 years

hey, thanks for this. I have a problem, when I go back from my launched activity, the calling one that had the webview would be finished? How can I make sure the activity containing the webview remain open on back navigation? EDIT: nvm, I had the noHistory set to true, thanks!
Atieh about 8 years

removing it did not help.
user2899094 over 7 years

the problem with this is that when i change the URL using loadURL during runtime, the shouldOverrideUrlLoading function/method is triggered. But we dont want this, we only want clicks to open externally, so there need to be a check to see if touched
Mateus Gondim almost 7 years

Note that shouldOverrideUrlLoading(WebView view, String url) is deprecated in API 24. Check this answer.
Arslan Ali over 4 years

Saved my life. Thank youuu
Jonas Erbe over 3 years

From the security perspective it is better to check which url's SHOULD open IN the webview and ALL OTHERS should open in the default browser.