What is the use case for flatMap vs map in kotlin

36,060

Solution 1

Consider the following example: You have a simple data structure Data with a single property of type List.

class Data(val items : List<String>)

val dataObjects = listOf(
    Data(listOf("a", "b", "c")), 
    Data(listOf("1", "2", "3"))
)

flatMap vs. map

With flatMap, you can "flatten" multiple Data::items into one collection as shown with the items variable.

val items: List<String> = dataObjects
    .flatMap { it.items } //[a, b, c, 1, 2, 3]

Using map, on the other hand, simply results in a list of lists.

val items2: List<List<String>> = dataObjects
    .map { it.items } //[[a, b, c], [1, 2, 3]] 

flatten

There's also a flatten extension on Iterable<Iterable<T>> and also Array<Array<T>> which you can use alternatively to flatMap when using those types:

val nestedCollections: List<Int> = 
    listOf(listOf(1,2,3), listOf(5,4,3))
        .flatten() //[1, 2, 3, 5, 4, 3]

Solution 2

There are three functions in play here. map(), flatten(), and flatMap() which is a combination of the first two.

Consider the following example

data class Hero (val name:String)
data class Universe (val heroes: List<Hero>)

val batman = Hero("Bruce Wayne")
val wonderWoman = Hero (name = "Diana Prince")

val mailMan = Hero("Stan Lee")
val deadPool = Hero("Wade Winston Wilson")

val marvel = Universe(listOf(mailMan, deadPool))
val dc = Universe(listOf(batman, wonderWoman))

val allHeroes: List<Universe> = listOf(marvel, dc)

Map

allHeroes.map { it.heroes }
// output: [[Hero(name=Stan Lee), Hero(name=Wade Winston Wilson)], [Hero(name=Bruce Wayne), Hero(name=Diana Prince)]]

Map allows you to access each universe in {allHeroes} and (in this case) return its list of heroes. So the output will be a list containing two lists of heroes, one for each universe. The result is a List>

Flatmap

allHeroes.flatMap { it.heroes } 
// output: [Hero(name=Stan Lee), Hero(name=Wade Winston Wilson), Hero(name=Bruce Wayne), Hero(name=Diana Prince)]

FlatMap allows you to do the same as map, access the two lists of heroes from both universes. But it goes further and flattens the returned list of lists into a single list. The result is a List

Flatten

allHeroes.map { it.heroes }.flatten() 
// output: [Hero(name=Stan Lee), Hero(name=Wade Winston Wilson), Hero(name=Bruce Wayne), Hero(name=Diana Prince)]

This produces the same result as flatMap. So flatMap is a combination of the two functions, map{} and then flatten()

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lannyf
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Updated on February 27, 2020

Comments

  • lannyf
    lannyf about 4 years

    in https://try.kotlinlang.org/#/Kotlin%20Koans/Collections/FlatMap/Task.kt

    it has sample of using flatMap and map

    seems both are doing the same thing, is there a sample to show the difference of using flatMap and map?

    the data type:

    data class Shop(val name: String, val customers: List<Customer>)
    
    data class Customer(val name: String, val city: City, val orders: List<Order>) {
        override fun toString() = "$name from ${city.name}"
    }
    
    data class Order(val products: List<Product>, val isDelivered: Boolean)
    
    data class Product(val name: String, val price: Double) {
        override fun toString() = "'$name' for $price"
    }
    
    data class City(val name: String) {
        override fun toString() = name
    }
    

    the samples:

    fun Shop.getCitiesCustomersAreFrom(): Set<City> =
        customers.map { it.city }.toSet()
        // would it be same with customers.flatMap { it.city }.toSet() ?
    
    val Customer.orderedProducts: Set<Product> get() {
        return orders.flatMap { it.products }.toSet()
        // would it be same with return orders.map { it.products }.toSet()
    }
    
  • IgorGanapolsky
    IgorGanapolsky almost 5 years
    What is the use of flatten vs flatMap?
  • Kristopher Noronha
    Kristopher Noronha almost 4 years
    Is there any performance difference between .map{ f }.flatten() vs .flatMap{ f } ?
  • Scott Driggers
    Scott Driggers over 3 years
    flatMap(function) is the same as map(function).flatten()
  • mochadwi
    mochadwi almost 3 years
    cmiiw the former: O(2n) time complexity (doing the first n on .map then .flatten) the latter: O(n) time complexity @KristopherNoronha
  • Kristopher Noronha
    Kristopher Noronha almost 3 years
    @mochadwi I think O notation ignores the constant, so both are O(n) as far as time is concerned... however I suspect memory/temp objects might paint a different story and that's probably the diffrentiating factor when working with large structures.
  • mochadwi
    mochadwi almost 3 years
    agreed, the actual differentiation factor was the space constraint