Where is java jre path specified in Windows 7?
Solution 1
Found a stackoverflow question which has the solution: JRE installation directory in Windows
Running where java
gives the output:
C:\>where java
C:\Windows\System32\java.exe
(Didn't realize windows had where
command just knew it didn't have which
.) Curious how java.exe ended up there.
Update
This oracle article, Deploying the JRE on Windows, states that the Java installer will copy java.exe into the system directory:
By default, the installer places a copy of the runtime environment in the C:\Program Files\Java\jre1.6.0 directory. In addition, if no more recent version is already installed on the machine, the installer puts copies of the java and javaw application-launcher executables in the Microsoft Windows system directory. (The system directory varies depending on the Microsoft Windows version, but is usually either C:\winnt\system32 or C:\windows\system.)
Solution 2
C:\Windows\system32\java.exe
is a pretty common location.
Related videos on Youtube
User
Updated on September 18, 2022Comments
-
User almost 2 years
I have java installed including jre 6 and 7 on Windows 7 64-bit. When I type
java -version
at the command line I get:C:\>java -version java version "1.6.0_22" Java(TM) SE Runtime Environment (build 1.6.0_22-b04) Java HotSpot(TM) 64-Bit Server VM (build 17.1-b03, mixed mode)
I wanted to make jre7 the default java from the command line so I went to edit my path when I notice java isn't specified anywhere in either System Variables or User Variables (nor is there a JAVA_HOME variable either). Also running
set
from the command line confirms this as the Path variable has no java directory. My java is stored in the normalC:\Program Files\Java\jre6
.So now I'm curious how is windows finding my current java on the command line?
-
Ishikawa Yoshi over 11 yearsit looks like that C:\Windows\System32\java.exe checked first, if you haven't got this file here, java.exe runs from your JDK path
-