Win bat file: How to add leading zeros to a variable in a for loop?
39,507
Solution 1
Prefix the string with zeros and then take the desired count of characters from the right side:
@echo off
set count=5
setlocal EnableDelayedExpansion
for /L %%i in (1, 1, %count%) do (
set "formattedValue=000000%%i"
echo !formattedValue:~-3!
)
Outputs:
001
002
003
004
005
Solution 2
Using the setlocal enabledelayedexpansion
, the solution is this:
@echo off
setlocal ENABLEDELAYEDEXPANSION
set count=5
for /L %%i in (1, 1, %count%) do (
echo %%i
set j=00%%i
rem to display intermediate values inside loop, surround with !
echo !j!
)
endlocal
Here is a good reference: http://blog.crankybit.com/why-that-batch-for-loop-isnt-working/
Author by
Cambiata
Updated on July 09, 2022Comments
-
Cambiata almost 2 years
Very simple, I guess... I need to get a usable variable by adding leading zeros to the loop index variable (%%i) below.
@echo off for /L %%i in (1, 1, 5) do ( echo %%i rem How to create a variable j here as a rem result of adding leading zeros to %%i? (001, 002, 003 etc.) ) pause
How? I've tried the following, but I can't get the value out of the %%i variable inte the var_ at a...
@echo off & setlocal enableextensions for /L %%i in (1, 1, 5) do ( echo %%i set var_=00000%%i set var_=%var_:~-5% echo %var_% ) pause