Zend Framework: How to find a table row by the value of a specified column?

17,768

Solution 1

$result = $db->fetchAll($where);

or if you are trying to retrieve only one row.

$result = $db->fetchRow($where);

You could also use the Zend_Db_Select Object, keeping the adapter a little further abstracted:

$db = $this->getDbTable();
$select = $db->select()->where('token = ?', $token);
$result = $db->fetchAll($select);

Solution 2

This can be easily done by creating select object and fetching a row using this object. It's well described in manual: http://framework.zend.com/manual/en/zend.db.select.html#zend.db.select.execute

Your code could look like:

$select = $this->getDbTable()->select()->where('token = ?', (string) $token);
$row = $this->getDbTable()->fetchRow($select);
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Mike
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Mike

Updated on June 04, 2022

Comments

  • Mike
    Mike almost 2 years

    I am implementing my model exactly like the quickstart guide.

    In my model I am trying to implement a findByToken() method. The current find() method accepts an $id parameter, but I want to find by the value of a different column.

    //excerpt from the quickstart guide
    public function find($id, Default_Model_Guestbook $guestbook)
    {
        $result = $this->getDbTable()->find($id);
        if (0 == count($result)) {
            return;
        }
        $row = $result->current();
        $guestbook->setId($row->id)
                  ->setEmail($row->email)
                  ->setComment($row->comment)
                  ->setCreated($row->created);
    }
    

    I tried doing something like this, but I don't think it worked:

    $db = $this->getDbTable();
    $where = $db->getAdapter()->quoteInto('token = ?', $token);
    $result = $db->find($where);
    

    What would be the proper way to find a row by the value of a specified column?