add leading zeros to a list of numbers in Python

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Apply the same zfill function in a list comprehension, like this

>>> [str(item).zfill(6) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']

Alternatively, you can use the string's format method, with format specifiers, like this

>>> ["{:06d}".format(item) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']

If you are going to do the formatting more often, then you can store that in a variable, like this

>>> formatter = "{:06d}".format
>>> [formatter(item) for item in data]
['000001', '000010', '000313', '004000', '051234', '123456']

If you are using Python 2.x, then you can use map and the formatter function, like this

>>> map(formatter, data)
['000001', '000010', '000313', '004000', '051234', '123456']

If you are using Python 3.x, map returns an iterable map object. So, you need to explicitly create a list, like this

>>> list(map(formatter, data))
['000001', '000010', '000313', '004000', '051234', '123456']
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Updated on July 05, 2022

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  • user2854008
    user2854008 almost 2 years

    I am new to Python. I am trying to adjust the format of a list which looks like below:

    data=[1,10,313,4000,51234,123456]
    

    and I would like to convert them to a list of strings with leading zeros:

    result=['000001','000010','000313','004000','051234','123456']
    

    each of the element has 6 digits.

    I know for a single number X, I can do:

    str(X).zfill(6)
    

    but I am not sure how to apply this to a list. I would like to solve this problem without using a for loop.

    Anyone could help? Thanks.