Check directory before creating file in puppet?

Question

I'm trying to make a function which directory/file will be created only when the first directory exists, of not it must be skipped because of failed dependence.

I've tried this "onlyif" workaround, but unfortunately it doesn't work with my function.

$check_directory = file("/path/to/directory")
if($check_directory != '') {
    file{"/path/to/config":
        ensure  =>  directory,
        mode    =>  0755,
    }
    file{"/path/to/config/a.conf":
        ensure  =>  file,
        mode    =>  0755,
        content =>  template("config_template.conf"),
    }
}

I've got an error:

Error: Is a directory - /path/to/directory

Is there a way to do any other if statement? Or any parameter? Thank you.

Solution

You should be able to simply use a require statement in your a.conf file resource:

file{"/path/to/directory":
    ensure  =>  directory,
    mode    =>  0755,
}

file{"/path/to/config":
    ensure  =>  directory,
    mode    =>  0755,
}
file{"/path/to/config/a.conf":
    ensure  =>  file,
    mode    =>  0755,
    content =>  template("config_template.conf"),
    require => File["/path/to/directory"],
}

This will make sure that the directory will be created before the file.

Comments

[skantana]

Thanks for the answer, but it's difference directory. I would like to check another path to configuration, not the one that will be created. if I do so, I will get .. Error: Could not find dependency

[FooBee]

Then you have to add a file resource for that new directory and then use require with that resource. See my edited answer.

[FooBee]

Sorry, now I got it. But the sample code you wrote doesn't use the onlyif trick you linked to. So I am still confused - what exactly did you try and what didn't work. Please read How to ask better questions on Serverfault to avoid wasting your and our time.