Convert unix timestamp in Python to datetime and make 2 Hours behind

Question

I have this code, recieve a unix timestamp from a server which is 2 hours ahead of my time. My time is SAST and theirs is GMT +2.

I convert this timestamp in python to a readable datetime like this

import datetime

unixtimestamp = 1507126064
datetime.datetime.fromtimestamp(unixtimestamp).strftime('%Y-%m-%d %H:%M:%S')

The problem is that this time comes back two hours ahead of me, so what would be the easiest way to minus two hours or make it local time.

Solution

With datetime.timedelta object:

from datetime import datetime, timedelta

unix_ts = 1507126064
dt = (datetime.fromtimestamp(unix_ts) - timedelta(hours=2)).strftime('%Y-%m-%d %H:%M:%S')
print(dt)

Comments

[Andrew Christopher]

seems to have worked like a charm ,do I replace import datetime with from datetime import datetime, timedelta ?

[RomanPerekhrest]

@AndrewChristopher, as you wish: you are able to import the entire module datetime (import datetime) OR to import just the needed submodules/objects from datetime import datetime, timedelta

[Andrew Christopher]

I keep getting errors on from datetime import datetime, timedelta

[Andrew Christopher]

is this correct import sys import datetime import time import socket import struct import MySQLdb import subprocess import glob from datetime import timedelta

[Andrew Christopher]

sorry for all on one line