Division of Polynomials in python
Solution 1
I've modified your code slightly, so now it returns the quotient and remainder.
FWIW, it would be fairly easy to create a polynomial class, and then you could do polynomial arithmetic using standard operators and functions...
#! /usr/bin/env python
''' Polynomial long division
From http://stackoverflow.com/questions/26173058/division-of-polynomials-in-python
A polynomial is represented by a list of its coefficients, eg
5*x**3 + 4*x**2 + 1 -> [1, 0, 4, 5]
Modified by PM 2Ring 2014.10.03
'''
def normalize(poly):
while poly and poly[-1] == 0:
poly.pop()
if poly == []:
poly.append(0)
def poly_divmod(num, den):
#Create normalized copies of the args
num = num[:]
normalize(num)
den = den[:]
normalize(den)
if len(num) >= len(den):
#Shift den towards right so it's the same degree as num
shiftlen = len(num) - len(den)
den = [0] * shiftlen + den
else:
return [0], num
quot = []
divisor = float(den[-1])
for i in xrange(shiftlen + 1):
#Get the next coefficient of the quotient.
mult = num[-1] / divisor
quot = [mult] + quot
#Subtract mult * den from num, but don't bother if mult == 0
#Note that when i==0, mult!=0; so quot is automatically normalized.
if mult != 0:
d = [mult * u for u in den]
num = [u - v for u, v in zip(num, d)]
num.pop()
den.pop(0)
normalize(num)
return quot, num
def test(num, den):
print "%s / %s ->" % (num, den)
q, r = poly_divmod(num, den)
print "quot: %s, rem: %s\n" % (q, r)
return q, r
def main():
num = [1, 5, 10, 10, 5, 1]
den = [1, 2, 1]
test(num, den)
num = [5, 16, 10, 22, 7, 11, 1, 3]
den = [1, 2, 1, 3]
quot = [5, 1, 3, 0, 1]
rem = [0, 5]
q, r = test(num, den)
assert quot == q
assert rem == r
if __name__ == '__main__':
main()
Solution 2
In case you're open to using an external library (I saw sympy mentioned above), numpy can easily solve this for you. numpy.polydiv
is what you'd need.
Example: https://numpy.org/doc/stable/reference/generated/numpy.polydiv.html
Orangeblue
Updated on June 14, 2022Comments
-
Orangeblue almost 2 years
I am stuck with division of polynomials in python. Here is code that I modified. The while loop couldnt work. This code only output the original L as r. If I remove the while loop, only the remainder from first time division was outputted. I tried a bunch of ways to make it work, but all failed. Any suggestions will be greatly appreciated. Thanks!
def GetDegree(poly): while poly and poly[-1] == 0: poly.pop() # normalize return len(poly)-1 def division(p1,p2): d1 = GetDegree(p1) d2 = GetDegree(p2) if d2 < 0 or d1<0: raise ZeroDivisionError if d1 > d2: S,L = p2,p1#obtain S with lower degree, L with higher degree else: S,L = p1,p2 d1 = GetDegree(L) d2 = GetDegree(S) while d1>0: q = [0]*d1 d = [0]*(d1 - d2) + S#shift short towards right by d1-d2 mult = q[d1 - d2] = L[-1] / float(d[-1])#get the result by dividing the first term of the dividend by the highest term of the divisor d = [coef*mult for coef in d]#multiply the above result by short L = [fabs( coefL - coefd ) for coefL, coefd in zip(L, d)]#return a new long by subtracting long with d d1 = GetDegree(L)#return new d1 r = L#return new long and keeping looping for there is no variable left and return as remainder return r
I want to input any random polynomials for the computation. However, when I modified it, the results still not right. Here is the test that I ran: num:[2,1,1,1] den:[1,1,2]. Print result was: quote:[0.25,0.5], rem:[1.75,0.25]. Here is the code that I modified for the case of input, based on the answer from PM 2Ring:
def normalize(poly): while poly and poly[-1] == 0: poly.pop() if poly == []: poly.append(0) def poly_divmod(num, den): #Create normalized copies of the args num = num[:] normalize(num) den = den[:] normalize(den) if len(num) >= len(den): #Shift den towards right so it's the same degree as num shiftlen = len(num) - len(den) den = [0] * shiftlen + den else: return [0], num quot = [] divisor = float(den[-1]) for i in range(shiftlen + 1): #Get the next coefficient of the quotient. mult = num[-1] / divisor quot = [mult] + quot #Subtract mult * den from num, but don't bother if mult == 0 #Note that when i==0, mult!=0; so quot is automatically normalized. if mult != 0: d = [mult * u for u in den] num = [u - v for u, v in zip(num, d)] num.pop() den.pop(0) normalize(num) return quot, num def test(num, den): print ("%s / %s ->" % (num, den)) q, r = poly_divmod(num, den) print ("quot: %s, rem: %s\n" % (q, r)) return q, r def main(): degree = int(input('Enter the degree of your polynomial 1:')) num = [] for i in range (0,degree+1): coefficient = int(input('Enter the coefficient for x^ %i ? ' %i)) num.append(coefficient) degree = int(input('Enter the degree of your polynomial 2:')) den = [] for i in range (0,degree+1): coefficient = int(input('Enter the coefficient for x^ %i ? ' %i)) den.append(coefficient) test(num, den) if __name__ == '__main__': main()
-
Orangeblue over 9 yearsHi, Thanks very much for the help! I want to input any random polynomials for the computation. However, when I modified it, the results still not right. Here is the test that I ran: num:[2,1,1,1] den:[1,1,2]. Print result was: quote:[0.25,0.5], rem:[1.75,0.25].
-
Orangeblue over 9 yearsThe code was only a part of all codes that suppose to run all add/sub/mult/division operation of polynomials. I have the polynomials class.
-
PM 2Ring over 9 yearsYou had me worried for a moment, Orangeblue! But I just checked it, and it is correct. I verified it by doing the division in a polynomial class I wrote about 6 years ago, and verifying that num == quot * den + rem. And to double-check that my Poly class isn't buggy I also did the division with pencil & paper. (x³ + x² + x + 2) / (2x² + x + 1) = 0.5x + 0.25, remainder 0.25x + 1.75.
-
DatRid over 9 yearsHi ZeldasLizard. Can you please extend your answer and describe what you changed and why, and how it helps the questioner ? Thank you! A side note: For formatting code, select the code and press
CRTL + K