Function pointer as parameter
115,411
Solution 1
The correct way to do this is:
typedef void (*callback_function)(void); // type for conciseness
callback_function disconnectFunc; // variable to store function pointer type
void D::setDisconnectFunc(callback_function pFunc)
{
disconnectFunc = pFunc; // store
}
void D::disconnected()
{
disconnectFunc(); // call
connected = false;
}
Solution 2
Replace void *disconnectFunc;
with void (*disconnectFunc)();
to declare function pointer type variable. Or even better use a typedef
:
typedef void (*func_t)(); // pointer to function with no args and void return
...
func_t fptr; // variable of pointer to function
...
void D::setDisconnectFunc( func_t func )
{
fptr = func;
}
void D::disconnected()
{
fptr();
connected = false;
}
Solution 3
You need to declare disconnectFunc as a function pointer, not a void pointer. You also need to call it as a function (with parentheses), and no "*" is needed.
Author by
Roland Soós
Updated on February 20, 2020Comments
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Roland Soós about 4 years
I try to call a function which passed as function pointer with no argument, but I can't make it work.
void *disconnectFunc; void D::setDisconnectFunc(void (*func)){ disconnectFunc = func; } void D::disconnected(){ *disconnectFunc; connected = false; }
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Roland Soós about 14 yearsThank you. Final code: void (*disconnectFunc)(); void D::setDisconnectFunc(void (*func)()){ disconnectFunc = func; } void D::disconnected(){ (*disconnectFunc)(); connected = false; }
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Dan about 14 years+1 for using my preferred syntax of de-referencing a function pointer (prefer disconnectFunc() to (*disconnectFunc)(), even though they're both fine)
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JavaRunner almost 11 yearsIs this portable way or it's not recommended to use for portability?
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GManNickG almost 11 years@JavaRunner: It's perfectly portable.
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JavaRunner almost 11 yearsFine. Thanks! Do you happen to know what I need to fix in that code if I need to pass function to setDisconnectFunc() with some parameters?
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GManNickG almost 11 years@JavaRunner: You should ask a new question if you need help extending it, the comment section is too constrained. There are many ways to do it, whatever your requirements are.
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gihanchanuka almost 9 yearsPutting this into a simple form with more understandable manner 1. learncpp.com/cpp-tutorial/78-function-pointers 2. newty.de/fpt/fpt.html (also about how to return a function pointer)