Generate random number between 1 and 3 / including 1 decimal place

Question

I can generate a random number between 1 and 3 fairly easy.

float x = Random.Range(1, 3);

But I am trying to generate a random number between 1 and 3, including 1 decimal place. i.e 1.0, 1.1, 1.2 - 2.8, 2.9, 3.0 Any help appreciate. I am finding no easy function to do this.

Note - I am using .cs script in Unity

Solution

You can multiply the result like this:

float result = rnd.Next(10, 31) * .1f;

This will result in a range from 1.0 to 3.0, stepping by .1.

Comments

[zmbq]

Change it to rnd.Next(10, 31), the upper limit is exclusive, not inclusive.

[Nathan A]

Ya, I just released that. Updating.

[user3609198]

Sorry I should have noted I am using a script in the Unity program to do this. Getter the error, 'UnityEngine.Random' does not contain a definition for 'Next' and not extension method 'Next' of type 'UnityEngine.Random' could be found.

[Nathan A]

Can't say I'm familiar with Unity, but it it's anything like C#, the concept should still work. Use your original method name Random.Range, but update the values and multiply like I mentioned. It should work.

[user3609198]

I think its working as its not throwing an error, now have code double result = Random.Range(-41, 41) * .1 Problem is the method Im putting it into 'transform.position', needs a float....The best overloaded method match for 'UnityEngine.Vector3(float,float, float)' has some invalid arguments

[Nathan A]

Ok, use a float instead: float result = Random.Range(-41, 41) * .1f

[user3609198]

Got it working with this, had to do a little trick to input float but method worked. Thanks