Making an array of random ints
113,040
You are never assigning the values inside the test2
array. You have declared it but all the values will be 0. Here's how you could assign a random integer in the specified interval for each element of the array:
int Min = 0;
int Max = 20;
// this declares an integer array with 5 elements
// and initializes all of them to their default value
// which is zero
int[] test2 = new int[5];
Random randNum = new Random();
for (int i = 0; i < test2.Length; i++)
{
test2[i] = randNum.Next(Min, Max);
}
alternatively you could use LINQ:
int Min = 0;
int Max = 20;
Random randNum = new Random();
int[] test2 = Enumerable
.Repeat(0, 5)
.Select(i => randNum.Next(Min, Max))
.ToArray();
Author by
Dante1986
Updated on September 17, 2020Comments
-
Dante1986 over 3 years
What i try to to, is generate an array of random int values, where the random values are taken between a min and a max.
So far i came up with this code:
int Min = 0; int Max = 20; int[] test2 = new int[5]; Random randNum = new Random(); foreach (int value in test2) { randNum.Next(Min, Max); }
But its not fully working yet. I think i might be missing just 1 line or something. Can anyone help me out pushing me in the right direction ?