How can I process command line arguments in Python?

54,721

Solution 1

As others answered, optparse is the best option, but if you just want quick code try something like this:

import sys, re

first_re = re.compile(r'^\d{3}$')

if len(sys.argv) > 1:

    if first_re.match(sys.argv[1]):
        print "Primary argument is : ", sys.argv[1]
    else:
        raise ValueError("First argument should be ...")

    args = sys.argv[2:]

else:

    args = ()

# ... anywhere in code ...

if 'debug' in args:
    print 'debug flag'

if 'xls' in args:
    print 'xls flag'

EDIT: Here's an optparse example because so many people are answering optparse without really explaining why, or explaining what you have to change to make it work.

The primary reason to use optparse is it gives you more flexibility for expansion later, and gives you more flexibility on the command line. In other words, your options can appear in any order and usage messages are generated automatically. However to make it work with optparse you need to change your specifications to put '-' or '--' in front of the optional arguments and you need to allow all the arguments to be in any order.

So here's an example using optparse:

import sys, re, optparse

first_re = re.compile(r'^\d{3}$')

parser = optparse.OptionParser()
parser.set_defaults(debug=False,xls=False)
parser.add_option('--debug', action='store_true', dest='debug')
parser.add_option('--xls', action='store_true', dest='xls')
(options, args) = parser.parse_args()

if len(args) == 1:
    if first_re.match(args[0]):
        print "Primary argument is : ", args[0]
    else:
        raise ValueError("First argument should be ...")
elif len(args) > 1:
    raise ValueError("Too many command line arguments")

if options.debug:
    print 'debug flag'

if options.xls:
    print 'xls flag'

The differences here with optparse and your spec is that now you can have command lines like:

python script.py --debug --xls 001

and you can easily add new options by calling parser.add_option()

Solution 2

Have a look at the optparse module. Dealing with sys.argv yourself is fine for really simple stuff, but it gets out of hand quickly.

Note that you may find optparse easier to use if you can change your argument format a little; e.g. replace debug with --debug and xls with --xls or --output=xls.

Solution 3

optparse is your best friend for parsing the command line. Also look into argparse; it's not in the standard library, though.

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Updated on April 25, 2020

Comments

  • user63503
    user63503 about 4 years

    What would be an easy expression to process command line arguments if I'm expecting anything like 001 or 999 (let's limit expectations to 001...999 range for this time), and few other arguments passed, and would like to ignore any unexpected?

    I understand if for example I need to find out if "debug" was passed among parameters it'll be something like that:

    if 'debug' in argv[1:]:
      print 'Will be running in debug mode.'
    

    How to find out if 009 or 575 was passed?

    All those are expected calls:

    python script.py
    python script.py 011
    python script.py 256 debug
    python script.py 391 xls
    python script.py 999 debug pdf
    

    At this point I don't care about calls like that:

    python script.py 001 002 245 568
    python script.py some unexpected argument
    python script.py 0001
    python script.py 02
    

    ...first one - because of more than one "numeric" argument; second - because of... well, unexpected arguments; third and fourth - because of non-3-digits arguments.