How do you escape apostrophe in single quoted string in bash?
Solution 1
In single quotes, no escaping is possible. There is no way how to include a single quote into single quotes. See Quoting in man bash.
Solution 2
In addition to POSIX-supported single- and double-quoting, bash
supplies an additional type of quoting to allow a small class of escaped characters (including a single quote) in a quoted string:
$ echo $'\'Hello World\''
'Hello World'
See the QUOTING section in the bash
man page, near the end of the section. (Search for "ANSI C".)
Solution 3
Simple example of escaping quotes in shell:
$ echo 'abc'\''abc'
abc'abc
$ echo "abc"\""abc"
abc"abc
It's done by closing already opened one ('
), placing escaped one (\'
) to print, then opening another one ('
).
Alternatively:
$ echo 'abc'"'"'abc'
abc'abc
$ echo "abc"'"'"abc"
abc"abc
It's done by finishing already opened one ('
), placing quote in another quote ("'"
), then opening another one ('
).
What you did ('\'Hello World\''
), is:
- Opened 1st apostrophe:
'
. - Closed right after it
\'
, so the string becomes:'\'
. -
Hello World
is not quotes. - Placed standalone apostrophe (
\'
) without opening it. - Last apostrophe (
'
) is opening string, but there is no closing one which is expected.
So the correct example would be:
$ echo \'Hello World\'
'Hello World'
Related: How to escape single-quotes within single-quoted strings?
Solution 4
To explain what is happening with your escaped apostrophes, we'll examine your second example (also see single quotes, or strong quotes):
$ echo '\'Hello World\''
> # expects you to continue input
Here, you've left the quotation hanging, as you've stated. Now trim the end and change it to:
v v v
$ echo '\'Hello World # Echo two strings: '\' and 'Hello World'.
\Hello World ^
The "Hello World" sub-string wasn't quoted here, but it behaved as if it was strong quoted. Using your example again, trim the end differently this time:
vv v (plain apostrophe)
$ echo '\'Hello World\' # Will echo: '\' and 'Hello World''
\Hello World' ^^ # Note that the trailing ' char is backslash escaped.
The "Hello World" sub-string again behaves as if it were strong quoted, with only the added apostrophe (escaped, so no longer a single quote) at the end.
When another single quote is added to the end (your original example) the string is left hanging and waiting for a close-quote.
TFchris
Updated on September 18, 2022Comments
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TFchris over 1 year
I would like to know if it is possible in R to convert a vector of characters to numerical values, and then convert those numerical values back to their original characters?
For example, my code is:
data <- c("red","blue","green","red","yellow") factor_data <- factor(data) num_data <- as.numeric(factor_data) print(num_data)
I would get
3 1 2 3 4
where blue = 1, green = 2, red = 3, yellow = 4
is there a way I can use
num_data
and get the corresponding character of colors to it?My attempt was the code:
(factor_data)[num_data]
but that just returned me:
green red blue green red
which is not the same as the original vector of colors.
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math over 11 years
echo \''Hello World'\'
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alistaire over 6 years
as.character(factor_data)
? ...or are you looking for something likesetNames(as.integer(factor(data)), data)
? -
TFchris over 6 yearsI am trying to use num_data to try and get back the colors. So if I were to have a random vector of integers from 1 to 4, i can change that vector of integers into a vector of corresponding colors
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Kibet over 11 yearsYou're right. The trick is in that line 'A single quote may not occur betweeen single quotes even when preceded by a backslash' So it probably splits it into different parts.
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zero2cx over 11 years@Colin As soon as a single quote is inside of two other single quotes (but backslashed), the quoted quote isn't a real quote anymore. It is just a char with no special pairing characteristics.
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choroba about 10 years@zero2cx: I would say "outside" instead of "inside".
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bufh over 9 years@choroba not "totally" true, in bash you can do
echo $'\'hello world\''
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Mikl over 4 yearsIt's great! Thx