How to convert _io.TextIOWrapper to string?

Question

I read the text format using below code,

f = open("document.txt", "r+", encoding='utf-8-sig')
f.read()

But the type of f is _io.TextIOWrapper. But I need type as string to move on.

Please help me to convert _io.TextIOWrapper to string.

Solution

You need to use the output of f.read().

string = f.read()

I think your confusion is that f will be turned into a string just by calling its method .read(), but that's not the case. I don't think it's even possible for builtins to do that.

For reference, _io.TextIOWrapper is the class of an open text file. See the documentation for io.TextIOWrapper.

---

By the way, best practice is to use a with-statement for opening files:

with open("document.txt", "r", encoding='utf-8-sig') as f:
    string = f.read()