How to disable tracking of formatting changes in Word for Mac 2011?
Solution 1
For Word: Go to the "Review" ribbon and click on the arrow section and select "Change tracking options". About 2/3rds of the way down, you'll see "Formatting". Just uncheck the "Track Formatting" box.
For Mac: Go to "Show Markup" on the review tab and uncheck "Formatting".
Solution 2
- Go to Review Ribbon
- Click on the arrow to the right of Show Markup
- You will see the following list of options:
Comments
Insertions and Deletions
Formatting
Markup Area Highlight
Reviewers
- Uncheck 'Formatting' and all the formatting notations will be eliminated
Solution 3
I went to the "customize tool bar" section (View --> toolbars--> Customize Toolbars and Menus), found an icon for "Accept All Changes in Document" and dragged it to my toolbar (this function eluded me everywhere else). Presto! It worked! You STILL have to uncheck "Markup" each time you enter the document, however. A royal pain.
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igor Smirnov
Updated on September 18, 2022Comments
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igor Smirnov over 1 year
Consider such type
type Last<TProps> = TProps extends [infer TProp] ? TProp : TProps extends [infer TProp, ... infer Rest] & PropertyKey[] ? Last<Rest> : never; export type L0 = Last<['a']>; // 'a' export type L1 = Last<['a', 'b']>; // 'b' export type L2 = Last<['a', 'b', 'c']>; // 'c'
It work as I expected. But if I want to restrict generic parameter - it fails
type Last<TProps extends PropertyKey[]> = TProps extends [infer TProp] ? TProp : TProps extends [infer TProp, ... infer Rest] ? Last<Rest> // error. 'Rest' does not satisfy the constraint 'PropertyKey[]' : never;
I tried to use & - it give no error, but output is not what i expected
type Last<TProps extends PropertyKey[]> = TProps extends [infer TProp] ? TProp : TProps extends [infer TProp, ... infer Rest] ? Last<Rest & PropertyKey[]> // no error : never; export type L0 = Last<['a']>; // 'a' export type L1 = Last<['a', 'b']>; // string | number | symbol export type L2 = Last<['a', 'b', 'c']>; // never
How I can use generic type constraint in conditional type to obtain such output
type Last<TProps extends PropertyKey[]> = ???? export type L0 = Last<['a']>; // 'a' export type L1 = Last<['a', 'b']>; // 'b' export type L2 = Last<['a', 'b', 'c']>; // 'c'
P.S. I know that in this example this constraint doesn't have much sense, but it is simpliest example that I find.
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WilliamKF over 10 yearsAre you on a Mac? I'm not locating and arrow section, nor do I find a
Change Tracking Options
item. -
Karen927 over 10 yearsMy apologies. I've edited my answer to include how it's done on a Mac.
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WilliamKF over 10 yearsThanks for the Mac answer, but the answer you supplied is one of the possible solutions that I said did not work in my question. Is this working for you? If so, what might be different in your environment?
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Karen927 over 10 yearsAre you using a template?
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WilliamKF over 10 yearsNot that I know of, how would I check?
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G-Man Says 'Reinstate Monica' about 9 yearsThis looks like little more than a restatement of the second paragraph of the answer from a year ago. Yours may be a little clearer, but doesn't really add any information.
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DavidPostill over 8 yearsWelcome to Super User! This is really a comment and not an answer to the original question. To critique or request clarification from an author, leave a comment below their post - you can always comment on your own posts, and once you have sufficient reputation you will be able to comment on any post.