ls everything that is _not_ a symlink

Question

Does ls have a way to show negated conditions like "all files which are not a symlink"? I use the latter a lot in a project directory but other negations would be useful as well.

For now, my research has only lead to creating an alias to something "like":

find . -maxdepth 1 ! -type l | sort # (...)

but obviously this way I don't get the colouring of ls, the column formatting, etc...

I am on Bash v3 on OS X 10.8.2 and Bash v4 on Pangolin sometimes.

Solution

Instead of piping it to sort, use ls.

find . -maxdepth 1 \! -type l -exec ls -d {} +

find . -maxdepth 1 \! -type l | xargs ls -d

If you used the zsh shell you could use their non-portable glob extensions:

ls -d *(^@)

Comments

[Admin]

See also: ls content of a directory ignoring symlinks

[JohnyMoraes]

Thx 4 the answer! Why do you escape !? It seems to be working even without.. What I am risking by not escaping it? Interesting how you use a final + and not \;, please explain?

[Random832]

@Robottinosino The + makes it send all to a single ls command instead of running it separately for each file (this way ls can do the columns and sorting). I escaped the ! because it is a special character to some shells even though yours seems to accept it fine.

[Random832]

@Robottinosino Edited with something zsh can do. I don't think bash can do it though.