Makefile string comparison #Ifeq

Question

In one of my projects, I am facing the error below. I have two environments and I'm observing the ifeq functionality difference between the two environments.

In the first environment, the below code is working fine.

FIRST = 1

ifeq ( ($FIRST),1 ) 

 ENABLE_CODE+= -D'ENABLE_PROGRAM'

endif

The same code is not working in the second environment. It only works if I modify the code

 ifeq ( ($FIRST),1)

to

 ifeq ( ( $FIRST),'1')

Could somebody help me to sort this out?

Solution

As told in the comment you should wrap FIRST into quotes: `$(FIRST). Note, the Makefile and Bash has different syntax. Makefile require round quotes around variable, bash - not.

Also please remove extra whitespaces inside ifeq. Note in some cases command ifeq ( $(FIRST),1 ) may compare with unstriped line and fail because of extra whitespaces: it may compare to '1 ' instead of simple '1'

So makefile will looks like

FIRST = 1

ifeq ($(FIRST),1)
   ENABLE_CODE += -D'ENABLE_PROGRAM'
endif

all:
        @echo FIRST $(FIRST)
        @echo ENABLE_CODE $(ENABLE_CODE)