Python: how to print range a-z?

Question

1. Print a-n: a b c d e f g h i j k l m n

2. Every second in a-n: a c e g i k m

3. Append a-n to index of urls{hello.com/, hej.com/, ..., hallo.com/}: hello.com/a hej.com/b ... hallo.com/n

Solution 1

>>> import string
>>> string.ascii_lowercase[:14]
'abcdefghijklmn'
>>> string.ascii_lowercase[:14:2]
'acegikm'

To do the urls, you could use something like this

[i + j for i, j in zip(list_of_urls, string.ascii_lowercase[:14])]

Solution 2

Assuming this is a homework ;-) - no need to summon libraries etc - it probably expect you to use range() with chr/ord, like so:

for i in range(ord('a'), ord('n')+1):
    print chr(i),

For the rest, just play a bit more with the range()

Solution 3

Hints:

import string
print string.ascii_lowercase

and

for i in xrange(0, 10, 2):
    print i

and

"hello{0}, world!".format('z')

Solution 4

for one in range(97,110):
    print chr(one)

Solution 5

Get a list with the desired values

small_letters = map(chr, range(ord('a'), ord('z')+1))
big_letters = map(chr, range(ord('A'), ord('Z')+1))
digits = map(chr, range(ord('0'), ord('9')+1))

or

import string
string.letters
string.uppercase
string.digits

This solution uses the ASCII table. ord gets the ascii value from a character and chr vice versa.

Apply what you know about lists

>>> small_letters = map(chr, range(ord('a'), ord('z')+1))

>>> an = small_letters[0:(ord('n')-ord('a')+1)]
>>> print(" ".join(an))
a b c d e f g h i j k l m n

>>> print(" ".join(small_letters[0::2]))
a c e g i k m o q s u w y

>>> s = small_letters[0:(ord('n')-ord('a')+1):2]
>>> print(" ".join(s))
a c e g i k m

>>> urls = ["hello.com/", "hej.com/", "hallo.com/"]
>>> print([x + y for x, y in zip(urls, an)])
['hello.com/a', 'hej.com/b', 'hallo.com/c']

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Comments

[Alex Willison]

To make this a tuple (which is immutable) in Python 3: tuple(string.ascii_lowercase)

[johk95]

I believe string.ascii_lowercase already worked in python 2.x, so to be sure just always use ascii_lowercase.

[John La Rooy]

@johk95, actually str.lowercase is locale dependent so wasn't the best choice in the first place. I've replaced it in my answer

[jonespm]

It looks like string.letters was removed in Python 3 and only string.ascii_letters, not exactly the same, is available

[Jeroen Heier]

Welcome to StackOverflow. Try to explain more clearly why this is a complete answer to the question.

[hmacias]

Thanks. I like it how you build this.

[Schroter Michael]

Hi, would be able to tell me whether is this only available in English? cant I get the same for other languages as well? Thanks & Best Regards