Python map() dictionary values
In Python 3, map
returns an iterator, not a list. You still have to iterate over it, either by calling list
on it explicitly, or by putting it in a for
loop. But you shouldn't use map
this way anyway. map
is really for collecting return values into an iterable or sequence. Since neither print
nor set.update
returns a value, using map
in this case isn't idiomatic.
Your goal is to put all the keys in all the counters in counters
into a single set. One way to do that is to use a nested generator expression:
s = set(key for counter in counters.values() for key in counter)
There's also the lovely dict comprehension syntax, which is available in Python 2.7 and higher (thanks Lattyware!) and can generate sets as well as dictionaries:
s = {key for counter in counters.values() for key in counter}
These are both roughly equivalent to the following:
s = set()
for counter in counters.values():
for key in counter:
s.add(key)
Taj Morton
Updated on July 09, 2022Comments
-
Taj Morton almost 2 years
I'm trying to use
map()
on thedict_values
object returned by thevalues()
function on a dictionary. However, I can't seem to be able tomap()
over adict_values
:map(print, h.values()) Out[31]: <builtins.map at 0x1ce1290>
I'm sure there's an easy way to do this. What I'm actually trying to do is create a
set()
of all theCounter
keys in a dictionary ofCounters
, doing something like this:# counters is a dict with Counters as values whole_set = set() map(lambda x: whole_set.update(set(x)), counters.values())
Is there a better way to do this in Python?