Randomizing a list in Python
36,895
Solution 1
from random import shuffle
list1 = [1,2,3,4,5]
shuffle(list1)
print list1
---> [3, 1, 2, 4, 5]
Solution 2
Use random.shuffle
:
>>> import random
>>> l = [1,2,3,4]
>>> random.shuffle(l)
>>> l
[3, 2, 4, 1]
Shuffle the sequence x in place. The optional argument random is a 0-argument function returning a random float in [0.0, 1.0); by default, this is the function random().
Solution 3
random.shuffle it!
In [8]: import random
In [9]: l = [1,2,3,4,5]
In [10]: random.shuffle(l)
In [11]: l
Out[11]: [5, 2, 3, 1, 4]
Author by
amrcsu
Updated on January 19, 2020Comments
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amrcsu over 4 years
I am wondering if there is a good way to "shake up" a list of items in Python. For example
[1,2,3,4,5]
might get shaken up / randomized to[3,1,4,2,5]
(any ordering equally likely).