Ruby warning: string literal in condition

Question

In the seventh line, I get the warning, "string literal in condition". What does the warning mean, and how can I resolve it?

   print 'Continue to use calculator?   Y or N'
   userAgree = gets.chomp
   if userAgree == 'Y' or 'y'
        userAgree = true
   else
        userAgree = false
   end

Solution 1

Change

if userAgree == 'Y' or 'y'

to

if userAgree == 'Y' or userAgree == 'y'

Or, cleaner and clearer in my opinion:

if userAgree.upcase() == 'Y'

Solution 2

Your if condition is not valid. This one works.

print 'Continue to use calculator?   Y or N'
userAgree = gets.chomp
if userAgree == 'Y' or userAgree == 'y'
  userAgree = true
else
  userAgree = false
end

Solution 3

you can make that:

    puts 'Continue to use calculator?   Y or N'
    userAgree = gets.chomp
    userAgree.to_s.upcase!

    def Check (ans)

    if ["Y","N"].include?(ans)
        puts"true"
    else
        puts "false"
    end

end

Check userAgree