take the first x elements of a dictionary on python

Question

I am a newbie on python, so I try to take the first 50 elements of a dictionary in python. I have a dictionary which is decreasing order sorted by value.

k=0
l=0
for k in len(dict_d):
    l+=1
    if l<51:
        print dict

for a small example:

 dict_d={'m':'3','k':'4','g':'7','d':'9'}

take the first 3 elements in a new dictionary:

 new_dict={'m':'3','k':'4','g':'7'}

I could not find how to do that?

Solution

dict_d = {...}
for key in sorted(dict_d)[:50]:
    print key, dict_d[key]

Comments

[user951487]

I want to take only the first 50 elements not whole dictionary !

[U2EF1]

For small dictionaries this is absolutely the pythonic way to do it. For larger ones though itertools.islice(dict_d, 50) is very much preferred.