TypeScript - how to inherit class and override lambda method
Solution 1
Well, you can't have that.
There's an issue that was opened but it was closed as "by design".
You should use regular methods:
class Base {
protected prop = null;
constructor() {
this.init();
this.initLambda();
}
init() {
console.log("Base init");
}
initLambda() {
console.log("Base initLambda");
}
}
class Derived extends Base {
constructor() {
super();
}
init() {
console.log("Derived init");
}
initLambda() {
console.log("Derived initLambda");
}
}
And then it will work.
As for keeping the right this
, you can always pass a call to the method as an arrow function:
doit() {
setTimeout(() => this.init(), 1);
}
Or use the Function.prototype.bind function:
setTimeout(this.init.bind(this));
Also, the _this
thing that the typescript compiler produces is just a hack to polyfil the arrow functions for ES5, but if you change the target to ES6 then it won't use it.
Edit:
You can save the bound methods as members:
class Base {
...
public boundInit: () => void;
constructor() {
...
this.boundInit = this.initLambda.bind(this);
setTimeout(this.boundInit, 500);
}
...
With that, when I do new Derived()
this is what I get:
Derived init
Derived initLambda // after 200 millis
Solution 2
The problem is that your lambda is a property.
When compiled to javascript, the Base
class becomes
var Base = (function () {
function Base() {
this.prop = null;
this.initLambda = function () {
console.log("Base initLambda");
};
this.init();
this.initLambda();
}
Base.prototype.init = function () {
console.log("Base init");
};
return Base;
}());
As you can see initLambda
is defined inside the constructor of Base
, so there is no way you can override that.
Calling super()
calls the Base
constructor which defines the this.initLambda
with the code in Base
and runs it. Hence your result.
View on playground
user210757
Updated on July 18, 2022Comments
-
user210757 almost 2 years
I have an inherited class, and need the parent to have a virtual method, which is overridden in the child class. This method is called from the base constructor, and needs access to instance properties, so it needs to be a lambda function, so "this" is "_this". The problem is, overriding a lambda method does not work for me like overriding a non-lambda does. Is this possible? If not, I'd like to understand why.
Also, will "this" always be the same as "_this" when the method is only called from the constructor?
class Base { protected prop = null; constructor() { this.init(); this.initLambda(); } init() { console.log("Base init"); } initLambda = () => { console.log("Base initLambda"); } } class Derived extends Base { constructor() { super(); } init() { console.log("Derived init"); } initLambda = () => { //let x = this.prop; console.log("Derived initLambda"); } }
Output:
Derived init
Base initLambda -
user210757 almost 8 yearsI guess you could say you CAN override it, but it's not overridden until instantiated.
-
Bruno Grieder almost 8 years@user210757 yes. Basically, don't call
this.initLambda()
in the Base constructor, override it inDerived
then call it fromDerived
-
user210757 almost 8 yearsAlong these lines, I thought this might work in the base constructor but did not - let x = () => this.initLambda(); x();
-
Nitzan Tomer almost 8 yearsYou can save bound functions like that as members and then use those. What do you by "not working"?
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user210757 almost 8 yearsDid not call the derived method - that is what I was trying to do.
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Nitzan Tomer almost 8 yearsCheck my revised answer
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benshabatnoam over 5 years'There's an issue that was opened but it was closed as "by design".' - the link is broken
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Nitzan Tomer over 5 years@benshabatnoam right, well, this post is pretty old... I have no idea if they recreated this issue (or what it was) in github.