Vector of shared pointers , memory problems after clearing the vector

65,169

Solution 1

you have two copies of shared_ptr<A> in this case, one is the sharedptr variable and the other as an element in the vector.

do this instead

test.push_back(std::move(sharedptr));

note now the original sharedptr has it's internal moved and no longer usable. The other thing is don't do anything at all, this is a perfectly valid usage of of shared_ptr and sharedptr will clean up itself after it goes out of scope.

Solution 2

The problem arises when the push_back adds a copy of the shared_ptr to the vector, leaving the original dangling until main exists. If you don't make the shared_ptr in main scope, the problem does not happen. Just avoid making the shared_ptr in main scope. Make it as a temporary right in the push_back call.

Output is now:   

constructor
I am almost there
destructor
I am here

New code:

#include <vector>
#include <iostream>
#include <memory>

using namespace std;

class A
{
public:
  A(){cout << "constructor" << endl;};
  ~A(){cout << "destructor"  << endl;};
};

int main( )
{
  vector<shared_ptr<A> > test;
  test.push_back(shared_ptr<A>(new A));
  cout << "I am almost there" << endl;
  test.clear();
  cout << "I am here" << endl;
  return 0;
}

Solution 3

Here sharedptr and the element in vector share the same object which will result in invoking constructor and destructor only once.

Solution 4

The reason the destructor isn't called until later is that your variable sharedptr is still in scope until the end of your main(). There are a few ways around this if you really want it cleaned up before then. The most obvious way to fix this is to only use sharedptr in a quick block scope:

int main( )
{
    std::vector<shared_ptr<A> > test;
    {
      shared_ptr<A> sharedptr (new A);
      test.push_back(sharedptr);
    }
    test.clear();
    cout << "I am here" << endl;
}

Or alternatively, never create the sharedptr variable at all:

int main( )
{
    std::vector<shared_ptr<A> > test;
    test.push_back( shared_ptr<A>(new A) );
    test.clear();
    cout << "I am here" << endl;
}
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Kadir Erdem Demir
Author by

Kadir Erdem Demir

I didn't mend to became one but it seems I am a nerd. And you know what, I like it.

Updated on May 09, 2020

Comments

  • Kadir Erdem Demir
    Kadir Erdem Demir almost 4 years

    I realized that after calling vector.clear() which hold shared pointers, the destructors of the object which own by shared_ptr is not being released.

    Code example can be seen below . Even vector.clear() being called, destructor called after shared pointer goes beyond the scope.My question is - do I have to delete all smart pointers inside the vector manually by resetting them? Is there any easier way that you can advice ?

    Output :   
    
    constructor
    I am here
    destructor
    
    Code:
    
    #include <vector>
    #include <iostream>
    #include <memory>
    
    using namespace std;
    
    class A
    {
    public:
        A(){cout << "constructor" << endl;};
        ~A(){cout << "destructor"  << endl;};
    };
    
    int main( )
    {
        shared_ptr<A> sharedptr (new A);
        std::vector<shared_ptr<A> > test;
        test.push_back(sharedptr);
    
        test.clear();
        cout << "I am here" << endl;
    }