What is a designated initializer in C?
Solution 1
Designated initialisers come in two flavours:
1) It provides a quick way of initialising specific elements in an array:
int foo[10] = { [3] = 1, [5] = 2 };
will set all elements to foo
to 0, other than index 3 which will be set to 1 and index 5 which will be set to 2.
2) It provides a way of explicitly initialising struct
members. For example, for
struct Foo { int a, b; };
you can write
struct Foo foo { .a = 1, .b = 2 };
Note that in this case, members that are not explicitly initialised are initialised as if the instance had static
duration.
Both are standard C, but note that C++ does not support either (as constructors can do the job in that language.)
Solution 2
The Designed Initializer came up since the ISO C99 and is a different and more dynamic way to initialize in C when initializing struct
, union
or an array
.
The biggest difference to standard initialization is that you don't have to declare the elements in a fixed order and you can also omit element.
From The GNU Guide:
Standard C90 requires the elements of an initializer to appear in a fixed order, the same as the order of the elements in the array or structure being initialized.
In ISO C99 you can give the elements in random order, specifying the array indices or structure field names they apply to, and GNU C allows this as an extension in C90 mode as well
Examples
1. Array Index
Standard Initialization
int a[6] = { 0, 0, 15, 0, 29, 0 };
Designed Initialization
int a[6] = {[4] = 29, [2] = 15 }; // or
int a[6] = {[4]29 , [2]15 }; // or
int widths[] = { [0 ... 9] = 1, [10 ... 99] = 2, [100] = 3 };
2. Struct or union:
Standard Initialization
struct point { int x, y; };
Designed Initialization
struct point p = { .y = 2, .x = 3 }; or
struct point p = { y: 2, x: 3 };
3. Combine naming elements with ordinary C initialization of successive elements:
Standard Initialization
int a[6] = { 0, v1, v2, 0, v4, 0 };
Designed Initialization
int a[6] = { [1] = v1, v2, [4] = v4 };
4. Others:
Labeling the elements of an array initializer
int whitespace[256] = { [' '] = 1, ['\t'] = 1, ['\h'] = 1,
['\f'] = 1, ['\n'] = 1, ['\r'] = 1 };
write a series of ‘.fieldname’ and ‘[index]’ designators before an ‘=’ to specify a nested subobject to initialize
struct point ptarray[10] = { [2].y = yv2, [2].x = xv2, [0].x = xv0 };
Guides
- designated-initializers-c | geeksforgeeks.org
- using-designated-initializers
- tutorialspoint.com | designated-initializers-in-c
user7349461
Updated on June 12, 2022Comments
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user7349461 almost 2 years
I know this might be a basic question.
I have an assignment that requires me to understand what a Designated initializers in C are and what it means to initialize a variable with one.
I am not familiar with the term and couldn't find any conclusive definitions.
What is a designated initializer in C?
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DeiDei over 6 yearsTake a look at this for further reading about C++. I believe it's well set for the next standard.
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Bathsheba over 6 years@AnttiHaapala: Need to dig out my standard for my final comment before the ruled line. (Alas I'm on the choo choo). I think it's correct.
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Antti Haapala -- Слава Україні over 6 yearsport70.net/~nsz/c/c11/n1570.html#6.7.9p9 at least unnamed structure members are uninitialized.
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abetancort almost 4 yearsThe members (of the variable) that are not explicitly initialized in the code will be automatically initialized by the compiler to 0. Much like all static and global variables are always automatically initialized to 0 when not done explicitly in the code.