Bash script execute wget with a variable inside it

Question

I'm trying to execute a wget command with a variable inside it but it just ignores it, any idea what am I doing wrong?

#!/bin/bash
URL=http:://www.myurl.com
echo $(date) 'Running wget...'
wget -O - -q "$URL/something/something2"

Solution 1

Four things:

1. Add quotes around your URL: http:://www.myurl.com ==> "http:://www.myurl.com"
2. Remove the double colon: "http:://www.myurl.com" ==> "http://www.myurl.com"
3. Get rid of the extra flags and hyphen on the wget command: "wget -O - -q "$URL/something/something2"" ==> wget "$URL/something/something2"
4. Add curly braces around your variable: "wget "$URL/something/something2"" ==> "wget "${URL}/something/something2""

This works:

#!/bin/bash
URL="http://www.google.com"
echo $(date) 'Running wget...'
wget "${URL}"

Solution 2

I use that code in IPython (colab):

URL = 'http:://www.myurl.com'
!wget {URL}

I wrote this answer because was searching it!)