# SELECT distinct values for multiple rows of same ID

12,365

## Solution 1

You can use this simple solution:

``````SELECT DISTINCT
a.id,
b.value AS SIGN_UP,
c.value AS FIRST_NAME,
d.value AS STREET
FROM tbl a
LEFT JOIN tbl b ON a.id = b.id AND b.field_name = 'sign_up'
LEFT JOIN tbl c ON a.id = c.id AND c.field_name = 'first_name'
LEFT JOIN tbl d ON a.id = d.id AND d.field_name = 'street'
``````

Just to be safe, I made the joins `LEFT JOIN`'s because I do not know if an id can have missing fields, in which case they will show up as `NULL` in our derived columns.

SQL-Fiddle Demo

## Solution 2

You could also try pivoting with the help of grouping and conditional aggregating:

``````SELECT
ID,
MAX(CASE FIELD_NAME WHEN 'sign_up'    THEN VALUE END) AS SIGN_UP,
MAX(CASE FIELD_NAME WHEN 'first_name' THEN VALUE END) AS FIRST_NAME,
MAX(CASE FIELD_NAME WHEN 'street'     THEN VALUE END) AS STREET
FROM atable
GROUP BY
ID
;
``````

## Solution 3

``````SELECT ids.ID AS ID,
sign_up.VALUE AS SIGN_UP,
first_name.VALUE AS FIRST_NAME,
street.VALUE AS STREET
FROM (SELECT DISTINCT ID FROM tableName) AS ids
LEFT JOIN tableName AS sign_up
ON (sign_up.ID = ids.ID AND
sign_up.FIELD_NAME = 'sign_up')
LEFT JOIN tableName AS first_name
ON (first_name.ID = ids.ID AND
first_name.FIELD_NAME = 'first_name')
LEFT JOIN tableName AS street
ON (street.ID = ids.ID AND
street.FIELD_NAME = 'street')
``````

The left joins will ensure that missing values will result in `NULL` cells, instead of an omission of the whole row. Not sure whether that is important in your application. If it is not, you can use an inner join and in particular get rid of the subquery to select all unique IDs. See my original answer from which I derived this.

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Updated on June 11, 2022

I have a table that looks like this:

``````ID | FIELD_NAME   | VALUE
23 |  sign_up     |  yes
23 |  first_name  |  Fred
23 |  street      |  Barber Lane
24 |  sign_up     |  no
24 |  first_name  |  Steve
24 |  street      |  Camaro St.
25 |  sign_up     |  yes
25 |  first_name  |  Larry
25 |  street      |  Huckleberry Ave
``````

I want to run a query that will select unique ID's and the values as named columns so it would appear like so:

``````ID   |   SIGN_UP   | FIRST_NAME  |  STREET           |
23   |     yes     |    Fred     |  Barber Lane      |
24   |     no      |    Steve    |  Camaro St.       |
25   |     yes     |    Larry    |  Huckleberry Ave. |
``````

Any help would be much appreciated!!