Serializing a scala object into a JSon String using lift-json

12,867

You can "decompose" a case class into JSON and then render it. Example:

scala> import net.liftweb.json.JsonAST._
scala> import net.liftweb.json.Extraction._
scala> import net.liftweb.json.Printer._    
scala> implicit val formats = net.liftweb.json.DefaultFormats

scala> case class MyBean(name: String, age: Int)
scala> pretty(render(decompose(MyBean("joe", 35))))
res0: String = 
{
  "name":"joe",
  "age":35
}

But sometimes it is easier to use DSL syntax:

scala> import net.liftweb.json.JsonDSL._
scala> val json = ("name" -> "joe") ~ ("age" -> 35)
scala> pretty(render(json))
res1: String = 
{
  "name":"joe",
  "age":35
}
Share:
12,867
Ali Salehi
Author by

Ali Salehi

Updated on June 07, 2022

Comments

  • Ali Salehi
    Ali Salehi almost 2 years

    I am wondering, would you please let me know how can I use lift-json to serialize a simple bean class into json string (I'm using v2.0-M1). I tried:

    val r = JsonDSL.pretty(JsonAST.render(myBean))
    

    and I am getting

    [error]  found   : MyBean
    [error]  required: net.liftweb.json.JsonAST.JValue
    
  • Martin Konicek
    Martin Konicek about 12 years
    What if it's not a case class?
  • ammills01
    ammills01 over 6 years
    With liftweb 3.1.0 this has moved from pretty(render()) to prettyRender(). You can also do compactRender(). Both are part of net.liftweb.json.JsonAST._