Serving image with flask
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Are you sure the image is indeed in the location ./, i.e. in the root of your project?
In any case, it is better to use Flask's url_for() method to determine URLs (see http://flask.pocoo.org/docs/api/#flask.url_for) This makes sure that when you move things around, the URLs don't break.
Author by
Shan-x
Updated on June 17, 2022Comments
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Shan-x almost 2 years
I have a program which generates an image. Now I want to use Flask to make this picture accessible to other users, but I can’t display this image with the following code:
#!/usr/bin/python2 #coding: utf-8 from flask import * app = Flask(__name__) #app.run(host='0.0.0.0') @app.route('/') def index(): return render_template('hello.html') if __name__ == '__main__': app.run(debug=True,host='0.0.0.0')My template hello.html is:
<!doctype html> <title>Hello from Flask</title> <h1>Hello World!</h1> <img src="./weather-plot.png">When I run this program and visit the page, I see this:
192.168.0.61 - - [10/Jul/2013 10:22:09] "GET / HTTP/1.1" 200 - 192.168.0.61 - - [10/Jul/2013 10:22:09] "GET /weather-plot.png HTTP/1.1" 200 -And in my browser I see the title, but not the picture. What’s wrong?
By the way, is there a better method to display a picture without anything else? Maybe I don’t have to use a template?