Unzip a zipped file on sd card in Android application

26,989

Solution 1

import android.util.Log; 
import java.io.File; 
import java.io.FileInputStream; 
import java.io.FileOutputStream; 
import java.util.zip.ZipEntry; 
import java.util.zip.ZipInputStream; 

/** 
 * 
 * @author jon 
 */ 
public class Decompress { 
  private String _zipFile; 
  private String _location; 

  public Decompress(String zipFile, String location) { 
    _zipFile = zipFile; 
    _location = location; 

    _dirChecker(""); 
  } 

  public void unzip() { 
    try  { 
      FileInputStream fin = new FileInputStream(_zipFile); 
      ZipInputStream zin = new ZipInputStream(fin); 
      ZipEntry ze = null; 
      while ((ze = zin.getNextEntry()) != null) { 
        Log.v("Decompress", "Unzipping " + ze.getName()); 

        if(ze.isDirectory()) { 
          _dirChecker(ze.getName()); 
        } else { 
          FileOutputStream fout = new FileOutputStream(_location + ze.getName()); 
          for (int c = zin.read(); c != -1; c = zin.read()) { 
            fout.write(c); 
          } 

          zin.closeEntry(); 
          fout.close(); 
        } 

      } 
      zin.close(); 
    } catch(Exception e) { 
      Log.e("Decompress", "unzip", e); 
    } 

  } 

  private void _dirChecker(String dir) { 
    File f = new File(_location + dir); 

    if(!f.isDirectory()) { 
      f.mkdirs(); 
    } 
  } 
} 

In your case::

String zipFilename = Environment.getExternalStorageDirectory() + "/files.zip"; 
String unzipLocation = Environment.getExternalStorageDirectory() + "/unzipped/"; 

Decompress d = new Decompress(zipFilename, unzipLocation); 
d.unzip(); 

Solution 2

To unpacking the password protected file use this library:

http://www.lingala.net/zip4j/download.php

it is so easy.

ZipFile zipFile = new ZipFile(YourZipFile);
if(zipFile.isEncrypted())
    zipFile.setPassword(Password);
zipFile.extractAll(Destination);

Solution 3

Other answers not really work on sdcard(Environment.getExternalStorageDirectory() != SDCARD) in kitkat and above. but you can use this code for api 21 and above! for more help to get zipDocumentFile read this :

/**
 * @return true->successful
 */
public static Boolean unzip(Context context, DocumentFile zipDocumentFile) {

    try {

        InputStream inputStream = context.getContentResolver().openInputStream(zipDocumentFile.getUri());
        assert inputStream != null;
        ZipInputStream zipInputStream = new ZipInputStream(new BufferedInputStream(inputStream, BUFFER_SIZE));

        ZipEntry ze;
        while ((ze = zipInputStream.getNextEntry()) != null) {
            if (ze.isDirectory()) {

                String[] paths = ze.getName().split("/");

                DocumentFile documentFile = null;
                for (String path : paths) {
                    if (documentFile == null) {
                        documentFile = zipDocumentFile.getParentFile().findFile(path);
                        if (documentFile == null)
                            documentFile = zipDocumentFile.getParentFile().createDirectory(path);
                    } else {
                        DocumentFile newDocumentFile = documentFile.findFile(path);
                        if (newDocumentFile == null) {
                            documentFile = documentFile.createDirectory(path);
                        } else {
                            documentFile = newDocumentFile;
                        }
                    }
                }

                if (documentFile == null || !documentFile.exists())
                    return false;

            } else {

                String[] paths = ze.getName().split("/");

                //Make Folders
                DocumentFile documentFile = null;
                for (int i = 0; i < paths.length - 1; i++) {
                    if (documentFile == null) {
                        documentFile = zipDocumentFile.getParentFile().findFile(paths[i]);
                        if (documentFile == null)
                            documentFile = zipDocumentFile.getParentFile().createDirectory(paths[i]);
                    } else {
                        DocumentFile newDocumentFile = documentFile.findFile(paths[i]);
                        if (newDocumentFile == null) {
                            documentFile = documentFile.createDirectory(paths[i]);
                        } else {
                            documentFile = newDocumentFile;
                        }
                    }
                }

                DocumentFile unzipDocumentFile;
                if (documentFile == null) {
                    unzipDocumentFile = zipDocumentFile.getParentFile().createFile(URLConnection.guessContentTypeFromName(ze.getName()), paths[paths.length - 1]);
                } else {
                    unzipDocumentFile = documentFile.createFile(URLConnection.guessContentTypeFromName(ze.getName()), paths[paths.length - 1]);

                }


                // unzip the file
                OutputStream outputStream = context.getContentResolver().openOutputStream(unzipDocumentFile.getUri());

                int read;
                byte[] data = new byte[BUFFER_SIZE];
                assert outputStream != null;
                while ((read = zipInputStream.read(data, 0, BUFFER_SIZE)) != -1)
                    outputStream.write(data, 0, read);

                zipInputStream.closeEntry();

            }
        }

        return true;

    } catch (Exception e) {
        e.printStackTrace();
        return false;
    }

}

Solution 4

This is slightly more cleaner version of Samir's code with using Apache's IOUtils.copy() for copying files and finally block. If you have large files in archive then better use IOUtils.copyLarge().

import org.apache.commons.io.IOUtils;

import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class ZipUtils {
    public static void unzip(InputStream is, File path) {
        checkDir(path);
        ZipInputStream zis = null;
        FileOutputStream fos = null;
        try {
            zis = new ZipInputStream(is);
            ZipEntry ze;
            while ((ze = zis.getNextEntry()) != null) {
                File entryFile = new File(path, ze.getName());
                if (ze.isDirectory()) {
                    checkDir(entryFile);
                } else {
                    fos = new FileOutputStream(entryFile);
                    IOUtils.copy(zis, fos);
                    fos.close();
                    fos = null;
                }
                zis.closeEntry();
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            if (zis != null) {
                try {
                    zis.close();
                } catch (IOException ignore) {
                }
            }
            if (fos != null) {
                try {
                    fos.close();
                } catch (IOException ignore) {
                }
            }
        }
    }

    private static void checkDir(File path) {
        if (!path.exists()) {
            path.mkdirs();
        } else if (!path.isDirectory()) {
            throw new IllegalArgumentException("Path is not directory");
        }
    }
}
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26,989
Suhail Larik
Author by

Suhail Larik

Updated on July 26, 2020

Comments

  • Suhail Larik
    Suhail Larik almost 4 years

    I have a zipped password protected a video file saved on sd card on android emulator. Now i want to unzip that video file on sd card through code. How can i achieve that? Any help or code? Thanks in advance

  • Suhail Larik
    Suhail Larik over 12 years
    Divyesh Thanks for reply. But still i m confused because my zipped file is password protected so how i will match that password to enter in the file?
  • Rafael Nobre
    Rafael Nobre almost 12 years
    Just a complement to your answer, the actual entry read and file writing could be done in chunks for much higher performance instead of byte by byte: byte[] buffer = new byte[4096]; for (int c = zin.read(buffer); c != -1; c = zin.read(buffer)) { fout.write(buffer, 0, c); }
  • LOG_TAG
    LOG_TAG almost 12 years
    @nobre do you think same code works for unzipping or unpacking the expansion APK Expansion Files obb files?
  • Jakub Bielan
    Jakub Bielan about 9 years
    Here is a Xamarin.Android version: gist.github.com/pauldendulk/18958a610adb50990d96