Wireless network cannot be enabled for Sony VAIO E series

12.04 wireless vaio

Solution 1

This is not invented by me, but credited to answers from others in the web. Thanks to them.

Initial problem:

Bought new Sony Vaio E Series. Installing using CD, Ubuntu 12.04. During installation wireless worked. After reboot NO!. Can not enable wireless.

http://www.dkvermalinux.in/2012/05/ubuntu-1204-lts-wifi-problem-hardware.html?showComment=1337448079507#c2311451036067978243

I found there:

rfkill list all

rfkill unblock all

rfkill list all, works, and show: soft blocking in 'acer-wireless: Wireless LAN, soft blocked: yes'

rfkill unblock all does not manage to change. After another rfkill list all, same status remains.

Then I learned from How to unblock something listed in rfkill?. Thanks, Leckensteyn.

sudo modprobe -r acer_wmi

It works. Wireless Networks works 'normal' as it should be.

Thanks everybody.

Regards,

Toni Ridwan

Solution 2

I had the same problem. My wireless option was grayed out in network manager.

Solution: Blacklist mac80211 and voilà!

Ubuntu 12 and sony vaio e 14 series

Samantha J T Star

Updated on September 18, 2022

Comments

Samantha J T Star over 1 year
I have the following call:
```
 $.extend($.fn.dataTableExt.oSort, {
        "datetime-uk-pre": function (a) {
            from = a.split(' ');
            var ukDatea = from[0].split('/');
            var ukTimea = from[1].split(':');
            return (ukDatea[2] + ukDatea[1] + ukDatea[0] + ukTimea[1] + ukTimea[0]) * 1;
        }
```
Can someone explain what the "from =" is doing here. I note that when I run JSHint then it tells me 'from' is not defined.
- Knowledge Cube almost 12 years
  
  Welcome to Ask Ubuntu! It might be useful to edit your question to include more information about your specific wireless hardware, as described in this answer. Thanks!
- bozdoz over 11 years
  
  try var from = a.split(' ');?
- zerkms over 11 years
  
  So you randomly put var in front of other variables?
- John Dvorak over 11 years
  
  @zerkms not randomly, just to make them defined.
- zerkms over 11 years
  
  @Jan Dvorak: I asked op, to clarify why they have 2 variables with var and one without.
- John Dvorak over 11 years
  
  @zerkms I don't think OP has written this code.
- Andrew Fox over 11 years
  
  looks to me like "from" is just a variable. Where is "a" coming from? Can you post some code where it shows "a" being used?
- Eric Frick over 11 years
  
  I think you've read so much linq
John Dvorak over 11 years

I think you're too optimistic with "it's probably declared somewhere"
Justin Morgan over 11 years

I have the good fortune to work with well-written code lately. Feels pretty nice. To be fair, I did qualify that with if they've used proper coding practices.
Oleg over 11 years

"Without the var you create a global variable" < not necessarily global. We are not sure about the context here. The from variable could be defined in a closure. If not defined anywhere, then yes, it becomes global.
Quentin over 11 years

@Oleg — If it was, then there would be a var from higher up the scope chain, which was covered in the answer.
Oleg over 11 years

I don't think the OP has provided the entire code. So it remains a viable assumption.
Quentin over 11 years

@Oleg — Either there is no var from, in which case it is a global, or there is a var from higher up the scope chain. Both cases are discussed in the answer.