Delete lines that come after a line with a specific pattern in Shell
Solution 1
This is very trivial with text processing utilities. For example, using sed
:
sed '1,/pattern/!d' file
Meaning, match every line from the first one to the one with pattern
and delete all the non-matched lines. So, replace pattern
with your pattern. If it contains /
, you need to escape those characters. For example, if the pattern is pattern-with/character
:
sed '1,/pattern-with\/character/!d' file
To actually edit files (rather than print the edited stream to stdout), you can use the -i
flag:
sed -i '1,/pattern/!d' file
You can make a backup of the original file by adding an extension for the old file to -i
. Take care here - you must not include a space before the extension.
sed -i.backup '1,/pattern/!d' file
sed
takes multiple filename arguments. For example, to act on all the non-hidden files in the current directory you could use:
sed -i '1,/pattern/!d' *
Solution 2
Another solution, using awk:
awk '/specific-pattern/{stop=1} stop==0{print}' < input_file >> output_file
While the variable stop
is 0 (which is is, by default), awk will print the current line. However, if the current line matches the regular expression /specific-pattern/, then stop
will be set to 1. This makes stop==0
untrue, so awk will no longer execute the print
statement.
Input is read from input_file and appended to output_file.
If you want to keep the line with the pattern, reverse the two parts of the awk script.
Solution 3
Thank you @Zanna
I found this solution :
for ((i=1;i < $count+1 ;i++))
sed -n '/PATTERN/q;p' $i.txt > file_out$i.txt
Thank you
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MGM
Updated on September 18, 2022Comments
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MGM over 1 year
I'm trying to delete all lines comes after a specific pattern in files.
I have many files, which all have the same structure:
Example:
file1
line 1 ... line x "here there is a specific pattern" ... EOF
file n
line 1 ... line x "here there is a specific pattern" ... EOF
I tried to get a simple solution, but since I have many files, I proceed with a long way :p
The pattern appears one time in each file.
So, I got all lines number which contains this pattern, and save in one file.
this is my code:
count=$(ls -f path_to_folder/*.txt | wc -l) echo "Number of txt file : $count" ### for ((i=1;i < $count+1 ;i++)) { vt=$(grep -n PATTERN $i.txt | cut -d : -f 1) echo $vt >> PATTERN_line.txt }
Every line in
PATTERN_line.txt
contains the line number, in each file, where the pattern exists.Now, I'm trying to use those numbers to delete all lines that come after the pattern to the file end.
This means I need to keep the file from the head to the patten line which must be included.
I appreciate your help
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Katu about 6 yearsHave a look at this and if the answers don't solve your problem, please edit it explaining why stackoverflow.com/questions/5227295/…
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Zanna about 6 years@Katu since this cannot be closed as a duplicate of that question, which is on another SE site, there is not much benefit in OP editing this question to show how it differs from that one.
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MGM about 6 years@Katu , yes I got the solution from this question
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Katu about 6 years@Zanna What is the correct thing to do in this situation? As you said, can't be a cross-site duplicate. Should I copy and paste the accepted answer in stackoverflow as an answer to this question with a reference link?
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Zanna about 6 years@Katu posting the link in a comment is enough. You can answer this question here however you wish! You can post content from the answers there blockquoted with appropriate attribution if you think it would be useful to do that.
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Zanna about 6 yearsI would expect that to delete the line with the pattern, but I thought you wanted to keep that line...
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Zanna about 6 years
grep
has a-q
flag (seeman grep
) and checking exit status is exactly whatif
does (seehelp if
) so you can write things likeif grep -q "$2"; then ...
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Robin Winslow over 4 yearsHow can we delete the matched line as well?
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Zanna over 4 years@RobinWinslow that can be done with
sed -n '/pattern/q;p'
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Nathan Wallace almost 4 years
sed '/pattern/q'
works just the same assed '1,/pattern/!d'
, right? Also,sed -n '/pattern/q:p'
isnt' working for me (GNU sed 4.8). What's the:p
part supposed to do? Edit Oh, I see from @mgm you probably meant;p
, right? I see thatsed -n '/pattern/q;p'
deletes all lines before the matched pattern. -
Zanna almost 4 years@NathanWallace yes I meant
;
and not:
(I edited my comment to fix it). Not sure about'/pattern/q'
but, it does seem to do the same thing (I have never really learned to useq
properly). I must do somesed
practice... -
Nathan Wallace almost 4 yearsYour answers and comments here have taught me a lot! The
q
command says "when you get a match, stop processing" the file, which is why it works for the original question. Your solution if you want to exclude the matching line works, I think, because the-n
silences normal output, but thep
puts it back for every line that doesn't match the pattern