Generating an ascending list of numbers of arbitrary length in python

Question

Is there a function I can call that returns a list of ascending numbers? I.e., function(10) would return [0,1,2,3,4,5,6,7,8,9]?

Solution 1

You want range().

Solution 2

range(10) is built in.

Solution 3

If you want an iterator that gives you a series of indeterminate length, there is itertools.count(). Here I am iterating with range() so there is a limit to the loop.

>>> import itertools
>>> for x, y in zip(range(10), itertools.count()):
...     print x, y
... 
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9

---

Later: also, range() returns an iterator, not a list, in python 3.x. in that case, you want list(range(10)).

Comments

[jupiar]

Answer is so tiny, and making it into a function would look like: def my_func(min, max): return list(range(min, max))

[PeJota]

@jupiar your comment should be the top level answer