Print a list in reverse order with range()?
Solution 1
use reversed()
function:
reversed(range(10))
It's much more meaningful.
Update:
If you want it to be a list (as btk pointed out):
list(reversed(range(10)))
Update:
If you want to use only range
to achieve the same result, you can use all its parameters. range(start, stop, step)
For example, to generate a list [5,4,3,2,1,0]
, you can use the following:
range(5, -1, -1)
It may be less intuitive but as the comments mention, this is more efficient and the right usage of range for reversed list.
Solution 2
You could use range(10)[::-1]
which is the same thing as range(9, -1, -1)
and arguably more readable (if you're familiar with the common sequence[::-1]
Python idiom).
Solution 3
For those who are interested in the "efficiency" of the options collected so far...
Jaime RGP's answer led me to restart my computer after timing the somewhat "challenging" solution of Jason literally following my own suggestion (via comment). To spare the curious of you the downtime, I present here my results (worst-first):
Jason's answer (maybe just an excursion into the power of list comprehension):
$ python -m timeit "[9-i for i in range(10)]"
1000000 loops, best of 3: 1.54 usec per loop
martineau's answer (readable if you are familiar with the extended slices syntax):
$ python -m timeit "range(10)[::-1]"
1000000 loops, best of 3: 0.743 usec per loop
Michał Šrajer's answer (the accepted one, very readable):
$ python -m timeit "reversed(range(10))"
1000000 loops, best of 3: 0.538 usec per loop
bene's answer (the very first, but very sketchy at that time):
$ python -m timeit "range(9,-1,-1)"
1000000 loops, best of 3: 0.401 usec per loop
The last option is easy to remember using the range(n-1,-1,-1)
notation by Val Neekman.
Solution 4
No sense to use reverse
because the range
function can return reversed list.
When you have iteration over n items and want to replace order of list returned by range(start, stop, step)
you have to use third parameter of range which identifies step
and set it to -1
, other parameters shall be adjusted accordingly:
- Provide
stop
parameter as-1
(it's previous value ofstop - 1
,stop
was equal to0
). - As start parameter use
n-1
.
So equivalent of range(n)
in reverse order would be:
n = 10
print range(n-1,-1,-1)
#[9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
Solution 5
for i in range(8, 0, -1)
will solve this problem. It will output 8 to 1, and -1 means a reversed list
Comments
-
ramesh.mimit about 3 years
How can you produce the following list with
range()
in Python?[9, 8, 7, 6, 5, 4, 3, 2, 1, 0]